Consider the following sequence of reactions to give the major product (X)
$\text{P}~\text{g}$ of the major product (X) formed is reacted with $\text{NaHCO}_3$ solution to liberate a gas which occupied $11.2~\text{dm}^3$ at STP.
$\text{P} = \_\_\_\_\_\_\_\_~\text{g}$.
(Given molar mass in $\text{g~mol}^{-1}$ $\text{H}: 1, \text{C}: 12, \text{O}: 16, \text{Cl}: 35.5$)
Step 1: Identify the reaction sequence
Starting compound: Benzene
(i) $ \mathrm{CH_3Cl/AlCl_3} $
Friedel–Crafts alkylation gives toluene
(ii) $ \mathrm{Cl_2/FeCl_3} $
Chlorination of toluene gives mainly p-chlorotoluene (major product)
(iii) $ \mathrm{K_2Cr_2O_7/H_2SO_4} $
Oxidation of side chain $(-CH_3)$ to $(-COOH)$
So final major product $(X)$ is:
$p$-chlorobenzoic acid
Formula:
$ \mathrm{C_7H_5ClO_2} $
Step 2: Reaction with NaHCO3_33
Carboxylic acid reacts as:
$ \mathrm{RCOOH + NaHCO_3 \rightarrow RCOONa + CO_2 + H_2O} $
Thus,
$1$ mole acid gives $1$ mole $CO_2$
Step 3: Calculate moles of CO2CO_2CO2
At STP:
$22.4 \text{ dm}^3 = 1 \text{ mole}$
Given:
$11.2 \text{ dm}^3$
So,
$ \text{moles of } CO_2 = \frac{11.2}{22.4} = 0.5 $
Hence,
$ \text{moles of acid} = 0.5 $
Step 4: Molar mass of product
For $ \mathrm{C_7H_5ClO_2} $:
$ = 7(12) + 5(1) + 35.5 + 2(16) $
$ = 84 + 5 + 35.5 + 32 $
$ = 156.5 \text{ g/mol}$
Step 5: Mass of product
$ P = 0.5 \times 156.5 = 78.25 \text{ g}$
Nearest integer:
$ \boxed{78} $
Final Answer:
$\boxed{78}$
Consider the following reactions sequence
When the product (P) is subjected to Carius analysis using $\text{AgNO}_3$, $1.0\text{ g}$ of the product (P) will produce __________ g of the precipitate of AgBr. (Nearest Integer)
(Given : molar mass in $\text{g mol}^{-1}$ C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108)
Among the following, how many hydrocarbon (s) with formula $C_{10}H_{16}$ which on reaction with acidic potassium permagenate yield(s) same product? ____________

On treatment of the following compound with a strong acid, the most susceptible site for bond cleavage is :-

The total number of optically active compounds formed in the following reaction is :-

The major products U and V in the following reaction are
