Match List I with List II.List I (Reactions) List II (Reagents) A. 
I. (i) oleum, (ii) $NaOH, \Delta$, (iii) $H^+$ B. $CH_3COOH \rightarrow CH_3CH_2OH$ II. (i) $O_3$, (ii) $H_2O/H^+$ C. $CH_3CH_2CH_2OH \rightarrow $ 
III. (i) $CH_3OH, H^+$, (ii) $H_2$, catalyst D. 
IV. (i) conc. $H_2SO_4, \Delta$, (ii) $H_2O$
A-II, B-III, C-IV, D-I
Correct matching:
A. Cumene → Phenol
Reagents: (i) O₂, (ii) H₂O/H⁺
So, A → II
B. CH₃COOH → CH₃CH₂OH
Reagents: (i) CH₃OH, H⁺, (ii) H₂, catalyst
So, B → III
C. CH₃CH₂CH₂OH → CH₃CH(OH)CH₃
First dehydration, then hydration: conc. H₂SO₄, Δ; then H₂O
So, C → IV
D. Benzene → Phenol
Reagents: oleum, NaOH, Δ, then H⁺
So, D → I
Final Answer:
A-II, B-III, C-IV, D-I
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Important Questions from Organic Chemistry
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Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below- Given below are two statements:
Statement I: Cross aldol condensation between two different aldehydes will always produce four different products.
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(Given: molar mass in $\text{g mol}^{-1}$ $\text{H} : 1, \text{C} : 12, \text{O} : 16$)
