
The problem asks to identify compounds P and Q based on their molecular formula ($C_8H_8O$) and chemical reaction properties.
Let's analyze the structure corresponding to the correct answer (Option 1), which is Acetophenone.
Acetophenone (P) fits all the described properties. Oxidation yields Benzoic acid (Q), which reacts with $NaHCO_3$. Other possible isomers with the formula $C_8H_8O$ might include phenolic ketones or aromatic aldehydes, but acetophenone is the structure that satisfies all given reaction conditions, especially the negative Fehling's test and the formation of an aromatic carboxylic acid upon oxidation.
Based on the analysis:
The structure corresponding to Acetophenone is given in Option 1.
Select the reagents that reduce nitriles to primary amines :
A. (i) $LiAlH_4$ ; (ii) $H_2O$
B. $Sn + HCl$
C. $H_2 / Ni$
D. $Na(Hg) / C_2H_5OH$
E. $Br_2 / \text{aq. } NaOH$
Choose the correct answer from the options given below :
The major product Z formed in the following sequence of reactions is :
$$C_2H_6 \xrightarrow{Cl_2, \text{UV light}} X \text{ (monochlorinated product)} \xrightarrow{NH_3} Y \xrightarrow{(i) NaNO_2, HCl, (ii) H_2O} Z$$
The correct IUPAC name of the following compound is :

In the following reaction sequence, X and Z respectively are :
The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are :
Two products X and Y are formed in the following reaction sequence.
The suitable method that can be used for the separation of products X and Y is :
| List I (Reactions) | List II (Reagents) |
A.![]() | I. (i) oleum, (ii) $NaOH, \Delta$, (iii) $H^+$ |
| B. $CH_3COOH \rightarrow CH_3CH_2OH$ | II. (i) $O_3$, (ii) $H_2O/H^+$ |
C. $CH_3CH_2CH_2OH \rightarrow $ ![]() | III. (i) $CH_3OH, H^+$, (ii) $H_2$, catalyst |
D. ![]() | IV. (i) conc. $H_2SO_4, \Delta$, (ii) $H_2O$ |
Match List I with List II.
The following two reactions give the same foul smelling product Z.
$$C_2H_5Cl \xrightarrow{X} Z$$

X and Z, respectively, are :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below