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Compound P ($C_8H_8O$) gives a red orange precipitate with 2,4-DNP reagent and it does not reduce Fehling's reagent. On drastic oxidation with chromic acid, P gives an aromatic product Q that produces effervescence on treating with aq. $NaHCO_3$. Compounds P and Q, respectively, are :

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is

 

Compound Identification Using Chemical Tests

The problem asks to identify compounds P and Q based on their molecular formula ($C_8H_8O$) and chemical reaction properties.

Analysis of Compound P Properties

  • Formula: $C_8H_8O$.
  • 2,4-DNP Test: A positive result (red-orange precipitate) indicates the presence of a carbonyl group (C=O), common in aldehydes and ketones.
  • Fehling's Test: A negative result means P is not a typical aldehyde (like aliphatic aldehydes). It could be a ketone or possibly a sterically hindered/electronically deactivated aromatic aldehyde.
  • Oxidation: Drastic oxidation with chromic acid ($CrO_3$) produces an aromatic product Q. This suggests P might have an oxidizable group, like an alkyl side chain on an aromatic ring, or a benzylic alcohol/ketone structure.
  • Product Q Property: Q produces effervescence with aqueous sodium bicarbonate ($NaHCO_3$), signifying the formation of carbon dioxide ($CO_2$). This indicates Q is an aromatic carboxylic acid.

Evaluating the Options

Let's analyze the structure corresponding to the correct answer (Option 1), which is Acetophenone.

  • Structure (Acetophenone): $C_6H_5COCH_3$
  • Molecular Formula: $C_8H_8O$. Matches.
  • Reactivity:
    • It's a ketone, so it gives a positive 2,4-DNP test.
    • Ketones do not reduce Fehling's reagent. Matches.
    • Oxidation of the methyl group adjacent to the carbonyl on the benzene ring yields benzoic acid. The reaction is: $C_6H_5COCH_3 \xrightarrow{CrO_3, H_2SO_4, \Delta} C_6H_5COOH$
    • Benzoic acid ($C_6H_5COOH$) is an aromatic carboxylic acid.
    • Benzoic acid reacts with $NaHCO_3$ to produce $CO_2$ gas (effervescence): $C_6H_5COOH + NaHCO_3 \rightarrow C_6H_5COONa + H_2O + CO_2 \uparrow$ Matches.

Acetophenone (P) fits all the described properties. Oxidation yields Benzoic acid (Q), which reacts with $NaHCO_3$. Other possible isomers with the formula $C_8H_8O$ might include phenolic ketones or aromatic aldehydes, but acetophenone is the structure that satisfies all given reaction conditions, especially the negative Fehling's test and the formation of an aromatic carboxylic acid upon oxidation.

Conclusion

Based on the analysis:

  • Compound P is Acetophenone.
  • Compound Q is Benzoic Acid.

The structure corresponding to Acetophenone is given in Option 1.

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