The major product of the following reaction in :
This question is built on drawn structures, so the options cannot be reproduced as text. The chemistry behind the official answer is explained below.
Pt(PPh3)4 is a 18-electron Pt(0) complex that readily loses two triphenylphosphine ligands in solution to generate the reactive 14-electron fragment Pt(PPh3)2. That fragment is the species which actually reacts.
C2(CF3)4 is perfluoro-2-butene, (CF3)2C=C(CF3)2. The four strongly electron-withdrawing CF3 groups make it an exceptionally good π acceptor, so it binds the electron-rich Pt(0) centre very strongly.
The product is the η2-alkene complex (Ph3P)2Pt(η2-C2(CF3)4), a trigonal-planar 16-electron Pt complex retaining just two phosphines. Because back donation from Pt into the alkene π* is so extensive with perfluorinated alkenes, the C-C bond lengthens towards a single bond and the carbons pyramidalise — the bonding is better described by the metallacyclopropane (Dewar-Chatt-Duncanson) limit than by simple side-on π coordination.
The correct option is therefore the one showing two PPh3 ligands retained on platinum with the perfluorinated alkene bound side-on through both carbons; options retaining all four phosphines, or showing two separate carbene units, do not correspond to this well-known substitution chemistry.
Per the official final answer key the answer is option (C).
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