The grouped data for the observation are The population skewnessClass: 1-3 3-5 5-7 Frequency: 2 1 2
is zero
The question asks us to determine the population skewness for a given set of grouped data. Skewness is a statistical measure that describes the asymmetry of the probability distribution of a real-valued random variable about its mean. A distribution is symmetrical if it looks the same on both sides of the mean. Positive skewness indicates a tail extending towards higher values, while negative skewness indicates a tail extending towards lower values. Zero skewness suggests a symmetrical distribution.
We are provided with the following grouped data:
| Class | Frequency (\(f_i\)) |
|---|---|
| 1-3 | 2 |
| 3-5 | 1 |
| 5-7 | 2 |
To calculate the population skewness for grouped data, one common method is to use the third central moment. The formula for the population skewness coefficient (\(\gamma_1\)) based on moments is:
\(\gamma_1 = \frac{\mu_3}{\sigma^3}\)
where \(\mu_3\) is the third central moment and \(\sigma\) is the population standard deviation.
The third central moment (\(\mu_3\)) for grouped data is approximated by:
\(\mu_3 = \frac{\sum f_i (m_i - \bar{x})^3}{N}\)
where:
First, let's find the midpoints (\(m_i\)) for each class:
Next, we calculate the total frequency \(N\):
\(N = 2 + 1 + 2 = 5\)
Now, let's calculate the population mean (\(\bar{x}\)):
\(\bar{x} = \frac{\sum f_i m_i}{N}\)
\(\sum f_i m_i = 4 + 4 + 12 = 20\)
\(\bar{x} = \frac{20}{5} = 4\)
The population mean is 4.
Now, we calculate the terms \((m_i - \bar{x})^3\) and \(f_i (m_i - \bar{x})^3\):
Calculate the sum \(\sum f_i (m_i - \bar{x})^3\):
\(\sum f_i (m_i - \bar{x})^3 = -16 + 0 + 16 = 0\)
Now, calculate the third central moment (\(\mu_3\)):
\(\mu_3 = \frac{\sum f_i (m_i - \bar{x})^3}{N} = \frac{0}{5} = 0\)
Since the third central moment (\(\mu_3\)) is 0, the population skewness (\(\gamma_1\)) is also 0, provided the standard deviation (\(\sigma\)) is not zero.
Let's quickly calculate the population variance (\(\sigma^2\)) to confirm \(\sigma \neq 0\):
\(\sigma^2 = \frac{\sum f_i (m_i - \bar{x})^2}{N}\)
\(\sum f_i (m_i - \bar{x})^2 = 8 + 0 + 8 = 16\)
\(\sigma^2 = \frac{16}{5} = 3.2\)
\(\sigma = \sqrt{3.2}\)
Since \(\sigma^2 = 3.2 \neq 0\), \(\sigma \neq 0\). Therefore, the population skewness is indeed 0.
A skewness of zero indicates that the distribution is symmetrical around its mean.
Based on our calculation, the population skewness is 0.
Our calculated value matches Option 1.
The calculated population skewness for the given grouped data is zero. This means the distribution of the data is symmetrical.
| Skewness Value | Distribution Shape |
|---|---|
| Zero Skewness | Symmetrical (e.g., Normal Distribution) |
| Positive Skewness (> 0) | Asymmetrical, tail extends to the right (towards higher values) |
| Negative Skewness (< 0) | Asymmetrical, tail extends to the left (towards lower values) |
Besides the moment-based coefficient (\(\gamma_1\)), other measures of skewness exist:
All these measures aim to quantify the degree and direction of asymmetry in a distribution. The choice of measure depends on the data and the specific context.
Following histogram shows certain frequency distribution against class intervals.

The approximated mean of this distribution is:
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The variation among the observations of each specific class is known as:
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Which of the following is a method of collection of primary data?
Which one is not basis of classification of data?
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In a test in Mathematics, 20% of the students obtained “first class”. If the data are represented by a Pie-Chart, what is the central angle corresponding to “first class”?
The following table gives the monthly expenditure of two families:
Expenditure (in Rs.) | ||
Items | Family A | Family B |
Food | 3,500 | 2,700 |
Clothing | 500 | 800 |
Rent | 1,500 | 1,000 |
Education | 2,000 | 1,800 |
Miscellaneous | 2,500 | 1,800 |
In constructing a pie diagram to the above data, the radii of the circles are to be chosen by which one of the following ratios?
In an examination, 40% of candidates got second class. When the data are represented by a pie chart, what is the angle corresponding to second class?
Following histogram shows certain frequency distribution against class intervals.

The approximated mean of this distribution is: