The grouped data for the observation are as follows. The population skewness:Class: 2-4 4-6 6-8 Frequency: 2 1 2
is zero
Let's analyze the provided grouped data to determine its population skewness. Skewness is a measure of the asymmetry of a probability distribution. It tells us if the data is skewed to the left (negative skew), skewed to the right (positive skew), or symmetric (zero skew).
The data is given in classes with corresponding frequencies:
| Class | Frequency |
|---|---|
| 2-4 | 2 |
| 4-6 | 1 |
| 6-8 | 2 |
To analyze the distribution of this grouped data, we typically use the midpoint of each class to represent the values within that class.
The midpoint of a class interval \([L, U]\) is calculated as \(\frac{L + U}{2}\), where \(L\) is the lower limit and \(U\) is the upper limit.
Now let's look at the midpoints and their corresponding frequencies:
| Midpoint (x) | Frequency (f) |
|---|---|
| 3 | 2 |
| 5 | 1 |
| 7 | 2 |
We can visualize this distribution:
The distribution has its highest frequencies (2) at the extreme midpoints (3 and 7) and a lower frequency (1) at the center midpoint (5). If we plot the frequency against the midpoint, we would see a shape that is symmetric around the midpoint 5. The distribution is balanced, with the same frequency (2) on the left side (midpoint 3) as on the right side (midpoint 7) relative to the central frequency (1 at midpoint 5).
A distribution is symmetric if the left side is a mirror image of the right side. For symmetric distributions, the mean, median, and mode are often equal (though not always required for symmetry itself). A key characteristic of symmetric distributions is that they have zero skewness.
In this case, the frequency distribution is perfectly symmetric around the central value (represented by midpoint 5). Therefore, the population skewness for this grouped data is zero.
| Concept | Explanation | Skewness Value |
|---|---|---|
| Symmetric Distribution | Data is evenly distributed around the center. Left and right sides are mirror images. | Zero skewness |
| Positively Skewed (Right Skew) | Tail is longer on the right side. Mean > Median > Mode. | Positive skewness |
| Negatively Skewed (Left Skew) | Tail is longer on the left side. Mean < Median < Mode. | Negative skewness |
While we determined skewness by observing the symmetry here, skewness can also be calculated mathematically. A common measure is Pearson's coefficient of skewness or the moment coefficient of skewness.
Pearson's First Coefficient of Skewness (for unimodal distribution):
\(SK_1 = \frac{\text{Mean} - \text{Mode}}{\text{Standard Deviation}}\)
Pearson's Second Coefficient of Skewness (generally applicable):
\(SK_2 = \frac{3 \times (\text{Mean} - \text{Median})}{\text{Standard Deviation}}\)
The moment coefficient of skewness (\(\gamma_1\)) is based on the third standardized moment:
\(\gamma_1 = E\left[\left(\frac{X - \mu}{\sigma}\right)^3\right]\)
For grouped data, these measures require calculating the mean, median, mode, and standard deviation from the frequency distribution, using the midpoints to represent the class values. However, recognizing symmetry provides a direct conclusion about zero skewness without needing these calculations.
The grouped data for the observation are
| Class: | 1-3 | 3-5 | 5-7 |
| Frequency: | 2 | 1 | 2 |
The population skewness
For the following frequency distribution
| Class: | 3-5 | 5-7 | 7-9 | 9-11 |
| Frequency: | 1 | 4 | 2 | 1 |
the value of mode is:
Which one is not basis of classification of data?
Which of the following options is correct when data is classified on the basis of attributes?
Which option is WRONG?
The arithmetic mean of the following frequency distribution of number of accidents Xon week working days is:
| X: | 2 | 4 | 6 | 8 | 10 | 12 |
| Frequency: | 3 | 4 | 2 | 1 | 4 | 2 |
The systematic (methodological) arrangement of the statistical data in columns or rows is called:
Mutual and unique variances among multiple factors can be embodied in a diagram that comprises overlapping circles. The diagram is known as:
Which statement of the following is incorrect?
The graphical representation of the time series is known as:
Consider the following LPP.:
Max Z = 15x 1 + 10x 2
Subject to the constraints
4x 1 + 6x 2 ≤ 360
3x 1 + 0x 2 ≤ 180
0x 1 + 5x 2 ≤ 200
x 1, x 2 ≥ 0
The solution of the LPP using Graphical solution-technique is :
A graph of a cumulative frequency distribution is called :
Which of the following is not an example of compressed data?
A cumulative frequency distribution is given below
Class | 60-62 | 63-65 | 66-68 | 69-71 | 72-74 |
Cumulative frequency | 3 | 20 | 36 | 48 | 50 |
Which one of the following class has maximum frequency?
The measure of the central tendency is given by the X-coordinate of the point of intersection of the more than ogive and less than ogive is: