To arrange the fractions $\frac{2}{3}, \frac{1}{2},$ and $\frac{1}{6}$ in ascending order, we need to compare their values. This is easiest done by converting them to equivalent fractions with a common denominator.
The denominators are 3, 2, and 6. The least common multiple (LCM) of these numbers is 6. We will convert each fraction so it has a denominator of 6.
Now we compare the fractions based on their numerators:
Comparing the numerators 4, 3, and 1, the ascending order is 1, 3, 4.
Arranging the fractions according to their ordered numerators gives us the ascending order:
$ \frac{1}{6}, \frac{3}{6}, \frac{4}{6} $Replacing the equivalent fractions with the original ones, the ascending order is:
$ \frac{1}{6}, \frac{1}{2}, \frac{2}{3} $Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: