To arrange the fractions $\frac{2}{3}, \frac{1}{2},$ and $\frac{1}{6}$ in ascending order, we need to compare their values. This is easiest done by converting them to equivalent fractions with a common denominator.
The denominators are 3, 2, and 6. The least common multiple (LCM) of these numbers is 6. We will convert each fraction so it has a denominator of 6.
Now we compare the fractions based on their numerators:
Comparing the numerators 4, 3, and 1, the ascending order is 1, 3, 4.
Arranging the fractions according to their ordered numerators gives us the ascending order:
$ \frac{1}{6}, \frac{3}{6}, \frac{4}{6} $Replacing the equivalent fractions with the original ones, the ascending order is:
$ \frac{1}{6}, \frac{1}{2}, \frac{2}{3} $What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |