The following 8051 assembly program is given. Answer the questions based on it.Line No. Mnemonics 1 MOV SP, #4F H 2 SET B PSW.3 3 MOV R0, #25H 4 MOV R1, #0AH 5 MOV R2, #06H 6 PUSH 8 7 PUSH 9 8 PUSH 0AH . . . V V 20 POP 8
What is the memory location of the stack where the first data byte will be stored?
50H
The rule for the 8051 stack. The stack grows upward in internal RAM, and on every PUSH the sequence is:
1. increment SP by one, then 2. write the data byte at the new address in SP.
So SP always points to the byte most recently stored — the current top of stack — and the next free location is SP + 1.
Apply it to this program. Line 1 set SP = 4FH. The first push in the program is line 6, \(\texttt{PUSH 8}\). When it executes:
\(SP \leftarrow 4FH + 1 = 50H\)
and the data byte is then written to address 50H.
Therefore the first data byte is stored at 50H, not at 4FH — location 4FH is never written to at all; it is merely the starting marker below the stack area.
Why pre-increment matters. Contrast this with a POP, which reverses the order: read the byte at SP first, then decrement SP. Together the two rules keep SP consistently pointing at the last valid entry, so a stack that has been pushed and popped equally often returns SP to its original value. Following the same rule, the next push (line 7) will use 51H and the one after that 52H, which is how the later questions in this set are answered.
Checking the distractors. 4FH ignores the pre-increment; 51H and 52H correspond to the second and third pushes.
Hence, the first data byte is stored at memory location 50H.
A microprocessor is a semiconductor chip fabricated with entire central processing unit (CPU) on it. It is a programmable device that accepts binary data from an input device, processes the data according to the instructions stored in the memory and provides results as output. Basically microprocessor performs two functions - (a) Fetches an instruction from the memory and (b) Performs the operation specified by the instruction. There are special inputs to the microprocessor called interrupts. External devices use these interrupts to get the microprocessor attention. A micro computer can be built by using 8085 microprocessor along with many other chips such as 8155, 8255, 8279, 8253, 8257, 8259, 8251 etc. 8085 microprocessor is 8-bit microprocessor which has 8-bit data registers where as 8086 is a 16-bit microprocessor.
The following 8051 assembly program is given. Answer the questions based on it.
| Line No. | Mnemonics |
| 1 | MOV SP, #4F H |
| 2 | SET B PSW.3 |
| 3 | MOV R0, #25H |
| 4 | MOV R1, #0AH |
| 5 | MOV R2, #06H |
| 6 | PUSH 8 |
| 7 | PUSH 9 |
| 8 | PUSH 0AH |
| . | |
| . | |
| . | |
| V | V |
| 20 | POP 8 |
| $D_7$ | $D_6$ | $D_5$ | $D_4$ | $D_3$ | $D_2$ | $D_1$ | $D_0$ |
In 8255 programmable peripheral interface device, if the port A and port B are to be set in a hand shake mode along with port C, what are the bits in the 8 bit control word to be set as 0 1 0.
The number system for the machine code of the microprocessor 8085 is
Which of the options in a multipurpose instruction used to implement the interrupt of 8085 and serial data input ?
Both 8155 and 8255 programmable peripheral interface ICs have the following common features :
(i) Programmable I/Os
(ii) Either port A or Port B can be set as either input or output ports.
(iii) One 14-bit down counter
(iv) AD0 – AD7 are multiplexed address/datalines.
Each instruction in an assembly program has the following fields :
(i) Lable field
(ii) Operand field
(iii) Comment field
(iv) Mnemonic field
Please write the proper sequence of fields :
The mnemonic of 8085 processor indicate :
| List – I | List – II |
| a. RLC | i. Rotate Accumulator Right through carry |
| b. RRC | ii. Rotate Accumulator Left through carry |
| c. RAR | iii. Rotate Accumulator Left |
| d. RAL | iv. Rotate Accumulator Right |
Codes :
Match the following :
| List – I (Pin terminals) | List – II (Applications) |
| a. SID, SOD | i. Wait state |
| b. READY | ii. Serial data transfer |
| c. TRAP | iii. Address Latch Control |
| d. ALE | iv. Interrupt |
Codes :
Assertion (A) : In serial communication system, when the transmission of data goes in both ways, it is called full-duplex system. Now if two micro processors are connected in full duplex mode, the amount of data transmitted will be double to the amount of data in half-duplex mode connection.
Reason (R) : When the transmission of data goes in one way, it is called half-duplex system and when the data moves in both ways, it is called full duplex system.
An 8086 address bus is a/an _____ -bit bus
Program counter for any counter:
In the pin out configuration of the 8085 microprocessor, the sequential input data is represented by
Which of the following functions is not performed by a microprocessor?
Match the columns.
Pin | Description |
a. D 0-D 7 | 1. Reset Input |
b. RESET | 2. Data Lines |
c. A 0,A 1 | 3. Internal Address |