An 8086 address bus is a/an _____ -bit bus
20
The question asks about the size of the address bus in an 8086 microprocessor. Understanding the address bus is crucial for comprehending how a microprocessor interacts with memory.
An address bus is a collection of electrical lines used by the central processing unit (CPU) to specify a physical address in memory or an input/output (I/O) device. The number of bits in the address bus determines the total amount of memory a microprocessor can directly access. Each unique address corresponds to a specific memory location.
The 8086 microprocessor is well-known for its specific architecture. It features a 20-bit address bus. This means that the 8086 has 20 separate lines dedicated to carrying address information. Each of these 20 lines can be either a 0 or a 1, allowing for a vast number of unique address combinations.
With a 20-bit address bus, the 8086 can generate $2^{20}$ unique memory addresses. To calculate the total memory capacity this allows, we perform the following calculation:
So, the 20-bit address bus of the 8086 allows it to directly address 1 Megabyte of physical memory space, from address 00000H to FFFFFH.
Beyond its address bus, the 8086 microprocessor has several other defining characteristics:
Based on the architecture of the 8086 microprocessor, its address bus is indeed 20-bit wide. This 20-bit address bus is a fundamental characteristic that defines its memory addressing capabilities and is a key distinguishing feature of the 8086 architecture.
Program counter for any counter:
In the pin out configuration of the 8085 microprocessor, the sequential input data is represented by
Which of the following functions is not performed by a microprocessor?
Match the columns.
Pin | Description |
a. D 0-D 7 | 1. Reset Input |
b. RESET | 2. Data Lines |
c. A 0,A 1 | 3. Internal Address |
Of the 128-byte internal RAM of the 8051 Microcontroller, how many bytes are bit addressable?