For the two-port network shown in figure, the z-parameter matrix is given by
\(\begin{bmatrix} 6 & 2 \\ 2 & 3 \end{bmatrix}\,\Omega\)
The network. It is a T-network: a 4 Ω resistor in series with port 1, a 2 Ω resistor shunting from the middle node down to the common rail, and a 1 Ω resistor in series with port 2.
Definition of the z-parameters. The impedance (open-circuit) parameters are defined by
\(V_1 = Z_{11}I_1 + Z_{12}I_2, \qquad V_2 = Z_{21}I_1 + Z_{22}I_2\)
so each parameter is measured with one port left open:
\(Z_{11}=\left.\dfrac{V_1}{I_1}\right|_{I_2=0},\ Z_{12}=\left.\dfrac{V_1}{I_2}\right|_{I_1=0},\ Z_{21}=\left.\dfrac{V_2}{I_1}\right|_{I_2=0},\ Z_{22}=\left.\dfrac{V_2}{I_2}\right|_{I_1=0}\)
Z11 — drive port 1, port 2 open. With I2 = 0 no current flows in the 1 Ω arm, so it drops no voltage and can be ignored. The current I1 flows through the 4 Ω series arm and then through the 2 Ω shunt arm:
\(Z_{11} = 4 + 2 = 6\ \Omega\)
Z22 — drive port 2, port 1 open. Now the 4 Ω arm carries no current, and I2 flows through the 1 Ω series arm and the 2 Ω shunt arm:
\(Z_{22} = 1 + 2 = 3\ \Omega\)
Z21 — transfer impedance. With port 2 open, all of I1 flows through the shunt 2 Ω resistor, and the open-circuit voltage at port 2 is the voltage across that shunt element (the 1 Ω arm drops nothing):
\(V_2 = 2 I_1 \Rightarrow Z_{21} = 2\ \Omega\)
Z12. The network contains only resistors, so it is reciprocal and \(Z_{12} = Z_{21} = 2\ \Omega\). Physically, the 2 Ω shunt arm is the branch common to both loops, and for a T-network the mutual term is always the shunt element.
Assemble the matrix.
\([Z] = \begin{bmatrix} 6 & 2 \\ 2 & 3 \end{bmatrix}\Omega\)
Quick check on the options. A reciprocal network must give a symmetric matrix (Z12 = Z21), which immediately rules out options 2, 3 and 4; only option 1 is symmetric, and its diagonal entries 6 Ω and 3 Ω match the series-plus-shunt sums computed above.
Shortcut worth memorising. For a T-network with series arms ZA (port 1), ZB (port 2) and shunt arm ZC: \(Z_{11}=Z_A+Z_C\), \(Z_{22}=Z_B+Z_C\), \(Z_{12}=Z_{21}=Z_C\).
Hence, the z-parameter matrix is [[6, 2], [2, 3]] Ω.
Read the following statements :
ST 1 : y-parameters can be obtained from Z parameters.
ST 2 : It is not necessary to define y-parameters separately.
Match the given lists :
| List – I | List – II |
| a. Condition of reciprocity | i. \(\dfrac{Z_{12}}{Z_{22}}\) |
| b. h12 | ii. Z12 = Z21 |
c. \(\begin{bmatrix}R&R\\R&R\end{bmatrix}\) | iii. Z |
| d. Condition of symmetry | iv. Z11 = Z22 |
Codes :
The T-parameters for the following cascaded network is :

The z parameters z11 and z21 for the 2-port network shown in the given figure respectively are :

The two port network mentioned below can be characterized by four variables V1, V2, I1 and I2, in which only two can be independent.

The h-parameters of the two port network possesses the following :
(a) Linear network should contain no independent sources.
(b) V1 and V2 are taken as independent variables.
(c) V1 and I2 are taken as independent variables.
(d) I1 and V2 are taken as independent variables.
Options :
Assertion (A) : In a two port network, with 4 terminals four types of parameters like impedance, admittance, hybrid and transmission are considered and they are related to each other.
Reason (R) : The assumption made for the above statement is that there are no independent sources and non-zero initial conditions within the linear port network.
Select your answer using the codes given below :
The [Y] parameters of the network shown below are given as :

A short-circuit admittance matrix of a two-port network is
\(\left[ {\begin{array}{} 0\\ {\frac{1}{2}} \end{array}\begin{array}{} { - \frac{1}{2}}\\ 0 \end{array}} \right]\)
The two-port network is
A two-port network has scattering parameters given \(\left[ s \right] = \left[ {\begin{array}{*{20}{c}} {{s_{11}}}&{{s_{12}}}\\ {{s_{211}}}&{{s_{22}}} \end{array}} \right]\). If the port 2 of the two-port is short-circuited, the s11 parameter for the resultant one-port network is
With 10 V dc connected at port A, the current drawn by 7 Ω connected at port B is
With 6 V dc connected at port A, 1 Ω connected at port B draws 7/3 A. If 8 V dc is connected to port A, the open circuit voltage at port B is
In a linear two – port network, when 10 V is applied to Port 1, a current of 4 A flows through Port 2 when it is short-circuited. When 5 V is applied to Port, a current of 1.25 A flows through a 1 Ω resistance connected across Port 2. When 3 V is applied to Port 1, then current (in Ampere) through a 2 Ω resistance connected across Port 2 is __________.