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Question

A two-port network has scattering parameters given \(\left[ s \right] = \left[ {\begin{array}{*{20}{c}} {{s_{11}}}&{{s_{12}}}\\ {{s_{211}}}&{{s_{22}}} \end{array}} \right]\). If the port 2 of the two-port is short-circuited, the s11 parameter for the resultant one-port network is

The correct answer is \(\frac{{{s_{11}} + {s_{11}}{s_{22}} - {s_{12}}{s_{21}}}}{{1 + {s_{22}}}}\)

A two-port network is a fundamental concept in microwave engineering and circuit analysis, characterized by its scattering parameters (S-parameters). These parameters describe how incident and reflected power waves interact at the network's ports. The question asks us to determine the modified \(s_{11}\) parameter when port 2 of the two-port network is short-circuited, effectively transforming it into a one-port network.

Scattering Parameters Definition

For a general two-port network, the relationship between the incident waves (\(a_1, a_2\)) and reflected waves (\(b_1, b_2\)) at its two ports is given by the following scattering parameter equations:

  • b 1 = s 11 a 1 + s 12 a 2 {b_1} = {s_{11}}{a_1} + {s_{12}}{a_2} $ (Equation 1)
  • b 2 = s 21 > a 1 + s 22 > a 2 {b_2} = {s_{21}}{a_1} + {s_{22}}{a_2} $ (Equation 2)

Here, \(s_{11}\), \(s_{12}\), \(s_{21}\), and \(s_{22}\) are the scattering parameters of the two-port network.

Short-Circuited Port Condition

When port 2 of the two-port network is short-circuited, it implies that the reflection coefficient at port 2 is -1. This means the reflected wave \(b_2\) is equal in magnitude but opposite in phase to the incident wave \(a_2\) at port 2. Therefore, the condition for a short-circuited port 2 is:

b 2 > = a 2 > {b_2} = -{a_2} $

Deriving S11 for the One-Port Network

Our objective is to find the new \(s_{11}\) for the resultant one-port network. This new \(s_{11}\) is the reflection coefficient at port 1, which is defined as \(\frac{b_1}{a_1}\) when port 2 is short-circuited.

Let's substitute the short-circuit condition (\(b_2 = -a_2\)) into Equation 2:

a 2 > = s 21 > a 1 > + s 22 > a 2 > -{a_2} = {s_{21}}{a_1} + {s_{22}}{a_2} $

Now, we rearrange the equation to express \(a_2\) in terms of \(a_1\):

a 2 > s 22 > > a 2 > = s 21 > > a 1 > -{a_2} - {s_{22}}{a_2} = {s_{21}}{a_1} $ a 2 > ( 1 + s 22 > > ) = s 21 > > a 1 > -{a_2}\left( {1 + {s_{22}}} \right) = {s_{21}}{a_1} $ a 2 > = s 21 > > 1 + s 22 > > a 1 > {a_2} = - \frac{{{s_{21}}}}{{1 + {s_{22}}}}{a_1} $

Next, substitute this expression for \(a_2\) into Equation 1:

b 1 > = s 11 > > a 1 > + s 12 > > ( s 21 > > 1 + s 22 > > a 1 > ) {b_1} = {s_{11}}{a_1} + {s_{12}}\left( { - \frac{{{s_{21}}}}{{1 + {s_{22}}}}{a_1}} \right) $ b 1 > = s 11 > > a 1 > s 12 > > s 21 > > 1 + s 22 > > a 1 > {b_1} = {s_{11}}{a_1} - \frac{{{s_{12}}{s_{21}}}}{{1 + {s_{22}}}}{a_1} $

To find the new \(s_{11}\) (let's denote it as \(s_{11}'\)), which is \(\frac{b_1}{a_1}\), we divide both sides by \(a_1\):

s 11 > > = b 1 > a 1 > = s 11 > > s 12 > > s 21 > > 1 + s 22 > > {s_{11}'} = \frac{{{b_1}}}{{{a_1}}} = {s_{11}} - \frac{{{s_{12}}{s_{21}}}}{{1 + {s_{22}}}} $

To simplify this expression and match the options, we combine the terms over a common denominator:

s 11 > > = s 11 > > ( 1 + s 22 > > ) > s 12 > > s 21 > > 1 + s 22 > > {s_{11}'} = \frac{{{s_{11}}\left( {1 + {s_{22}}} \right) - {s_{12}}{s_{21}}}}{{1 + {s_{22}}}} $ s 11 > > = s 11 > > + s 11 > > s 22 > > s 12 > > s 21 > > 1 + s 22 > > {s_{11}'} = \frac{{{s_{11}} + {s_{11}}{s_{22}} - {s_{12}}{s_{21}}}}{{1 + {s_{22}}}} $

This derived expression represents the \(s_{11}\) parameter for the resultant one-port network when port 2 is short-circuited.

Comparison with Options

Let's compare our derived expression with the given options:

Option Expression
1 \(\frac{{{s_{11}} - {s_{11}}{s_{22}} + {s_{12}}{s_{21}}}}{{1 + {s_{22}}}}\)
2 \(\frac{{{s_{11}} + {s_{11}}{s_{22}} - {s_{12}}{s_{21}}}}{{1 + {s_{22}}}}\)
3 \(\frac{{{s_{11}} + {s_{11}}{s_{22}} + {s_{12}}{s_{21}}}}{{1 - {s_{22}}}}\)
4 \(\frac{{{s_{11}} - {s_{11}}{s_{22}} + {s_{12}}{s_{21}}}}{{1 - {s_{22}}}}\)

The calculated \(s_{11}\) parameter, \(\frac{{{s_{11}} + {s_{11}}{s_{22}} - {s_{12}}{s_{21}}}}{{1 + {s_{22}}}}\), precisely matches option 2. This formula is fundamental for understanding how terminating one port of a two-port network with a short circuit affects the reflection coefficient at the other port.

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Important Questions from Two Port Networks

  1. A short-circuit admittance matrix of a two-port network is

    \(\left[ {\begin{array}{} 0\\ {\frac{1}{2}} \end{array}\begin{array}{} { - \frac{1}{2}}\\ 0 \end{array}} \right]\)

    The two-port network is

  2. With 10 V dc connected at port A, the current drawn by 7 Ω connected at port B is

  3. With 6 V dc connected at port A, 1 Ω connected at port B draws 7/3 A. If 8 V dc is connected to port A, the open circuit voltage at port B is

  4. In a linear two – port network, when 10 V is applied to Port 1, a current of 4 A flows through Port 2 when it is short-circuited. When 5 V is applied to Port, a current of 1.25 A flows through a 1 Ω resistance connected across Port 2. When 3 V is applied to Port 1, then current (in Ampere) through a 2 Ω resistance connected across Port 2 is __________.

  5. Which of the following transformation between the z (impedance) and h (hybrid) parameters is correct?

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