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A ray of light with wavelength $\lambda$ is incident on three different photo-electric cells namely 1, 2 and 3. The threshold wavelength of these photo-electric cells are $\lambda_1$, $\lambda_2$, and $\lambda_3$, respectively and the magnitude of stopping potentials of these cells are $V_1$, $V_2$ and $V_3$, respectively. The relation between $\lambda$ and threshold wavelengths are $\lambda_1 < \lambda$, $\lambda_2 > \lambda$ and $\lambda_3 \gg \lambda$. The correct option is :

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
$V_1 = 0, V_2 < V_3$

To solve this problem, we need to evaluate the conditions given for the three photoelectric cells based on their threshold wavelengths and their stopping potentials.

  1. We are given that the incident light wavelength is \(\lambda\). The threshold wavelengths are \(\lambda_1, \lambda_2,\) and \(\lambda_3\) for cells 1, 2, and 3, respectively.
  2. The conditions given are:
    • \(\lambda_1 < \lambda\): Here, the incident wavelength is longer than the threshold wavelength. This means cell 1 cannot emit photoelectrons as the photon energy is less than the work function. Therefore, \(V_1 = 0\).
    • \(\lambda_2 > \lambda\): The incident wavelength is shorter than the threshold, indicating that cell 2 can emit photoelectrons as the photon energy is sufficient to overcome the work function, resulting in a non-zero stopping potential, \(V_2 > 0\).
    • \(\lambda_3 \gg \lambda\): Here, the incident wavelength is much shorter than the threshold wavelength. This condition ensures that cell 3 can also emit photoelectrons with much higher energy, resulting in a higher stopping potential, \(V_3 > V_2\).
  3. Calculating energies:
    • For photoelectric emission, the energy of the incident photon, \(E = \frac{hc}{\lambda}\), must be greater than the work function \(W_0 = \frac{hc}{\lambda_{\text{threshold}}}\) to emit electrons.
    • Stopping potential is given by \(eV = E - W_0\), where \(e\) is the electron charge.
  4. Thus, the correct option is:
    • \(V_1 = 0, V_2 < V_3\)
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