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Question

A Kelvin thermometer and a Fahrenheit thermometer both give the same reading for a certain sample. What would be the corresponding reading in a Celsius thermometer?

This question was previously asked in
NDA I 2017 GAT Previous Year Paper (23-Apr-2017)
The correct answer is

301

Finding Temperature When Kelvin and Fahrenheit Scales Align

The question asks for the corresponding reading on a Celsius thermometer when a sample has the same temperature reading on both Kelvin and Fahrenheit thermometers. Let this common reading on the Kelvin and Fahrenheit scales be \( T \). So, \( K = T \) and \( F = T \), where \( K \) is the temperature in Kelvin and \( F \) is the temperature in Fahrenheit.

We need to find the temperature in Celsius, denoted by \( C \), at this condition \( K=F \).

We use the standard conversion formulas between the three temperature scales:

  • From Celsius to Kelvin: \( K = C + 273 \)
  • From Celsius to Fahrenheit: \( F = \frac{9}{5}C + 32 \)

Since we are given that the Kelvin reading (\( K \)) and the Fahrenheit reading (\( F \)) are the same, we can set the right-hand sides of the conversion formulas (expressed in terms of Celsius) equal to each other:

Substitute \( K = C + 273 \) and \( F = \frac{9}{5}C + 32 \) into the condition \( K = F \):

\[ C + 273 = \frac{9}{5}C + 32 \]

Now, we need to solve this equation for \( C \). Let's rearrange the terms to group the \( C \) terms on one side and the constant terms on the other:

\[ 273 - 32 = \frac{9}{5}C - C \]

\[ 241 = \left(\frac{9}{5} - 1\right)C \]

\[ 241 = \left(\frac{9}{5} - \frac{5}{5}\right)C \]

\[ 241 = \frac{4}{5}C \]

To find \( C \), we multiply both sides by \( \frac{5}{4} \):

\[ C = \frac{241 \times 5}{4} \]

\[ C = \frac{1205}{4} \]

\[ C = 301.25 \]

So, the temperature reading in Celsius is 301.25 °C when the Kelvin and Fahrenheit thermometers show the same reading.

Looking at the given options, the value 301.25 is closest to 301.

Let's verify the readings for \( C = 301.25 \):

  • Kelvin: \( K = C + 273 = 301.25 + 273 = 574.25 \) K
  • Fahrenheit: \( F = \frac{9}{5}C + 32 = \frac{9}{5}(301.25) + 32 = 1.8 \times 301.25 + 32 = 542.25 + 32 = 574.25 \) °F

Indeed, at 301.25 °C, the Kelvin and Fahrenheit readings are both 574.25. Since 301 is the closest integer option to 301.25, it is the correct choice.

Key Temperature Conversion Formulas

Conversion Formula
Celsius to Kelvin \( K = C + 273 \)
Kelvin to Celsius \( C = K - 273 \)
Celsius to Fahrenheit \( F = \frac{9}{5}C + 32 \)
Fahrenheit to Celsius \( C = \frac{5}{9}(F - 32) \)
Kelvin to Fahrenheit \( F = \frac{9}{5}(K - 273) + 32 \)
Fahrenheit to Kelvin \( K = \frac{5}{9}(F - 32) + 273 \)

Revision Table: Temperature Scale Conversion

Understanding the relationships between different temperature scales is crucial. The key formulas allow us to convert a temperature value from one scale to another.

  • The Celsius scale is widely used and based on the freezing point (0 °C) and boiling point (100 °C) of water at standard atmospheric pressure.
  • The Kelvin scale is the base unit of temperature in the International System of Units (SI). It is an absolute scale, meaning 0 K (absolute zero) is the theoretical point where particle motion stops. The steps are the same size as Celsius degrees.
  • The Fahrenheit scale is commonly used in the United States. Water freezes at 32 °F and boils at 212 °F.

Additional Information on Temperature Scales

Absolute zero is 0 K, which corresponds to -273.15 °C and -459.67 °F. While conversions often use 273 for simplicity, the more precise value is 273.15.

The size of one degree Celsius is the same as the size of one Kelvin. A change of 1 °C is equal to a change of 1 K.

The size of one degree Fahrenheit is \( \frac{5}{9} \) times the size of one degree Celsius or Kelvin.

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