The problem asks us to find the percentage of work completed by a group of 60 men working for 6 days, given the rate at which 20 men complete the same work.
First, we determine the total amount of work required, measured in 'man-days'. This represents the effort needed to complete the entire piece of work.
Total Work = (Number of men) \times (Number of days)
Given: 20 men can do the work in 45 days.
Total Work = 20 \text{ men} \times 45 \text{ days} = 900 \text{ man-days}
Next, we calculate the amount of work done by the second group of men in the specified time.
Work Done = (Number of men) \times (Number of days)
Given: 60 men work for 6 days.
Work Done = 60 \text{ men} \times 6 \text{ days} = 360 \text{ man-days}
Finally, we calculate the percentage of the total work that was completed by the 60 men in 6 days.
Percentage Work Done = \left( \frac{\text{Work Done}}{\text{Total Work}} \right) \times 100\%
Percentage Work Done = \left( \frac{360 \text{ man-days}}{900 \text{ man-days}} \right) \times 100\%
Percentage Work Done = \left( \frac{36}{90} \right) \times 100\%
Percentage Work Done = \left( \frac{4}{10} \right) \times 100\%
Percentage Work Done = 0.4 \times 100\% = 40\%
Therefore, 60 men complete 40% of the total work in 6 days.
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