$\frac{7}{9}, \frac{6}{7}, \frac{22}{25}, \text{ and } \frac{11}{13}$
The question asks to identify the largest fraction among the given options: $\frac{7}{9}, \frac{6}{7}, \frac{22}{25}, \text{ and } \frac{11}{13}$.
To find the largest fraction, we can convert each fraction into its decimal form. This allows for a direct comparison of their values.
Convert each fraction to a decimal:
Now, compare the decimal values obtained:
Comparing these decimals, we can see that $0.88$ is the largest value.
The decimal $0.88$ corresponds to the fraction $\frac{22}{25}$. Therefore, $\frac{22}{25}$ is the largest fraction among the given options.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |