$\frac{7}{9}, \frac{6}{7}, \frac{22}{25}, \text{ and } \frac{11}{13}$
The question asks to identify the largest fraction among the given options: $\frac{7}{9}, \frac{6}{7}, \frac{22}{25}, \text{ and } \frac{11}{13}$.
To find the largest fraction, we can convert each fraction into its decimal form. This allows for a direct comparison of their values.
Convert each fraction to a decimal:
Now, compare the decimal values obtained:
Comparing these decimals, we can see that $0.88$ is the largest value.
The decimal $0.88$ corresponds to the fraction $\frac{22}{25}$. Therefore, $\frac{22}{25}$ is the largest fraction among the given options.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: