What is the total resistance in the following circuit element?
3R/2
The correct answer is option "4"
Concept :
Resistance:
There are mainly two ways of the combination of resistances:
1. Resistances in series:

2. Resistances in parallel:

\(\frac{1}{{{R_{eff}}}} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}\)
Series Combination | Parallel Combination |
In series, voltage is divided through each of the connected resistors. | In parallel, the current is divided through each connected resistor. |
In series, the Current will be the same throughout the circuit. | In parallel, the Voltage will be the same throughout the circuit. |
Calculation:

In the given figure of resistance two identical resistances "R" are in parallel and then in series with otherr identical resistance "R"
The parallel combination of R and R would be
R' = R×R/(R + R)
R' = R/2
The R' is in a series with R.
So R equivalent would be
Req = R/2 + R
= 3R/2
Consider the following part of an electric circuit:

The total electrical resistance in the given part of the electric circuit is
Consider the following circuit:

Which one of the following is the value of the resistance between points A and B in the circuit given above?
Three wires each of length \(L\), cross-sectional area \(A\) and resistivity \(\rho\) are connected as shown in the figure.
These are to be replaced by another wire of same resistivity such that the resistance between points \(X\) and \(Z\) does not change. If \(L_1\) is the length and \(A_1\) is the cross-sectional area of the new wire, then which one among the following is correct?
Consider the following electric circuit:

Two equal resistors R are connected in parallel, and a battery of 12 V is connected across this combination A dc current of 100 mA flows through the circuit as shown below:

The value of R is
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The equivalent resistance of the circuit will be
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