All Exams Test series for 1 year @ ₹349 only
Question

Two resistors R 1 and R 2 arranged in parallel combination in an electrical closed circuit are made of the same material and of the same thickness. If the length of R 2 is twice the length of R 1, then the total resistance R satisfies

This question was previously asked in
NDA I 2022 GAT Previous Year Paper (10-Apr-2022)
The correct answer is 3R = 2R 1

Analyzing Resistors in Parallel Combination

The question describes a circuit with two resistors, $R_1$ and $R_2$, connected in parallel. We are given specific information about their physical properties: they are made of the same material and have the same thickness. This means they have the same resistivity ($\rho$) and the same cross-sectional area ($A$). We are also told that the length of $R_2$ is twice the length of $R_1$, which can be written as $L_2 = 2L_1$. We need to find the relationship between the total resistance ($R$) of the parallel combination and the individual resistances.

Understanding Electrical Resistance

The resistance of a conductor is determined by its material, length, and cross-sectional area. The formula for resistance is:

$$R = \rho \frac{L}{A}$$

where:

  • $R$ is the resistance.
  • $\rho$ (rho) is the resistivity of the material.
  • $L$ is the length of the conductor.
  • $A$ is the cross-sectional area of the conductor.

Relating $R_1$ and $R_2$

Given that $R_1$ and $R_2$ are made of the same material and have the same thickness (same cross-sectional area $A$), their resistances can be written as:

  • For $R_1$: $R_1 = \rho \frac{L_1}{A}$
  • For $R_2$: $R_2 = \rho \frac{L_2}{A}$

We know that $L_2 = 2L_1$. Substituting this into the expression for $R_2$:

$$R_2 = \rho \frac{2L_1}{A}$$

We can rewrite this as:

$$R_2 = 2 \times \left( \rho \frac{L_1}{A} \right)$$

Since $R_1 = \rho \frac{L_1}{A}$, we can substitute $R_1$ into the equation for $R_2$:

$$R_2 = 2R_1$$

So, the resistance of $R_2$ is twice the resistance of $R_1$.

Calculating Total Resistance in Parallel

For two resistors connected in parallel, the total resistance $R$ is given by the formula:

$$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2}$$

Alternatively, the total resistance can be calculated using the product-sum formula:

$$R = \frac{R_1 R_2}{R_1 + R_2}$$

Finding the Relationship between Total Resistance and $R_1$

We found that $R_2 = 2R_1$. Now, substitute this relationship into the parallel resistance formula $R = \frac{R_1 R_2}{R_1 + R_2}$:

$$R = \frac{R_1 (2R_1)}{R_1 + 2R_1}$$

Simplify the expression:

$$R = \frac{2R_1^2}{3R_1}$$

Cancel out one $R_1$ term from the numerator and the denominator:

$$R = \frac{2R_1}{3}$$

To match the format of the options, we can rearrange this equation by multiplying both sides by 3:

$$3R = 2R_1$$

Comparing with Options

Let's compare our derived relationship $3R = 2R_1$ with the given options:

  • Option 1: $3R = 2R_1$
  • Option 2: $3R = 2R_2$
  • Option 3: $2R = 3R_1$
  • Option 4: $2R = 3R_2$

Our result $3R = 2R_1$ matches Option 1.

Revision Table: Resistance Concepts

Concept Description Formula
Resistance (R) Opposition to electric current flow. $R = \rho \frac{L}{A}$
Resistivity ($\rho$) Intrinsic property of a material indicating its resistance. Unit: Ohm-meter ($\Omega \cdot m$)
Resistance in Series Total resistance is the sum of individual resistances. $R_{total} = R_1 + R_2 + \dots + R_n$
Resistance in Parallel Reciprocal of total resistance is the sum of reciprocals of individual resistances. $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots + \frac{1}{R_n}$

Additional Information: Factors Affecting Resistance and Circuit Types

Understanding the factors affecting resistance and how components behave in series versus parallel is crucial for circuit analysis.

  • Factors Affecting Resistance: The resistance of a conductor depends on four main factors:
    • Material: Different materials have different resistivities. Good conductors like copper have low resistivity, while insulators like rubber have high resistivity.
    • Length (L): Resistance is directly proportional to length. A longer wire offers more resistance.
    • Cross-sectional Area (A): Resistance is inversely proportional to the cross-sectional area. A thicker wire (larger area) offers less resistance.
    • Temperature: For most metallic conductors, resistance increases with increasing temperature.
  • Series Circuits: Components are connected end-to-end, forming a single path for current.
    • Current is the same through all components.
    • Total voltage is the sum of individual voltage drops.
    • Total resistance is the sum of individual resistances ($R_s = R_1 + R_2 + \dots$).
  • Parallel Circuits: Components are connected across each other, providing multiple paths for current.
    • Voltage is the same across all components.
    • Total current is the sum of currents through individual branches.
    • Total resistance is calculated using the reciprocal formula ($\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \dots$). The total resistance in parallel is always less than the smallest individual resistance.
Was this answer helpful?

Similar Questions

  1. An electric wire of resistance 50 ohm is cut into five equal wires. These wires are then connected in parallel. What is the equivalent resistance of this combination?
  2. Three equal resistors are connected in parallel configuration in a closed electrical circuit. Then the total resistance in the circuit becomes

  3. A metallic wire having a resistance of 20Ω is cut into two equal parts in length. These parts are then connected in parallel. The resistance of this parallel combination is equal to


Important Questions from Combination of Resistors — Series and Parallel

  1. Consider two resistors, $R_1$ and $R_2$, connected in series to a DC voltage source. Which of the following statements accurately describes the distribution of current and voltage across these resistors?

  2. A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:

  3. Two bulbs A, of (100w, 100v), and B of (60 w, 100v) are connected in series and across the series combination 200 v is applied. Which bulb will be fused?

  4. 3 resistors of 3 ohm each connected in series. What is the mean values of resistors?

  5. The equivalent resistance of the resistances (two) joined in parallel is 6/5 Ω. When one of the resistance wire is broken, the effective resistance becomes 2Ω. The resistance of the wire that got broken was :

Need Expert Advice?
Upcoming Exams
NDA
September 13, 2026
CDS
September 13, 2026
Test Series
NDA img
Defence
NDA 2026 Mock Test Series (Latest Pattern)
501 Tests 1 Tests Free
664 Attempts
4.6(121)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App