Consider the following circuit: The equivalent resistance of the circuit will be
CONCEPT :
Resistance:
Series combination of the resistance:

⇒ R = R 1+ R 2 ...(1)
The parallel combination of the resistance:

\(⇒ \frac{1}{R} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}\;\;\;\;\; \ldots \left( 2 \right)\)
EXPLANATION :
Given: R 1 = 2 Ω, R 2 = 4 Ω, R 3 = 6 Ω

\(⇒ \frac{1}{R} = \frac{1}{2} + \frac{1}{4} + \frac{1}{6}\)
⇒ R = 12/11 Ω

⇒ Rnet = 12/11 + 8
⇒ R net = 100/11 Ω = \(9\frac{1}{{11}}\Omega \)
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The value of R is
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