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Question

Three equal resistors are connected in parallel configuration in a closed electrical circuit. Then the total resistance in the circuit becomes

This question was previously asked in
NDA I 2021 GAT Previous Year Paper (18-Apr-2021)
The correct answer is

one-third of the individual resistance.

When electrical components like resistors are connected in a circuit, the way they are connected affects the total or equivalent resistance of the circuit. There are two primary ways to connect resistors: in series and in parallel.

Understanding Parallel Resistors

In a parallel connection, resistors are connected across the same two points in a circuit. This means that the voltage across each resistor is the same, but the current may divide among them. The total resistance in a parallel circuit is calculated differently than in a series circuit.

The formula for calculating the total equivalent resistance ($R_{total}$) when resistors are connected in parallel is given by the reciprocal of the sum of the reciprocals of individual resistances. For resistors $R_1, R_2, R_3, \dots, R_n$ connected in parallel, the formula is:

\begin{equation} \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \dots + \frac{1}{R_n} \end{equation}

Calculating Total Resistance for Three Equal Resistors in Parallel

The question describes a specific scenario: three equal resistors connected in a parallel configuration. Let's denote the resistance of each individual resistor as $R$. Since the three resistors are equal, we have $R_1 = R_2 = R_3 = R$.

Now, we can apply the parallel resistance formula for three resistors:

\begin{equation} \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \end{equation}

Substitute the individual resistance $R$ into the formula:

\begin{equation} \frac{1}{R_{total}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} \end{equation}

To sum the fractions on the right side, since they have a common denominator ($R$), we add the numerators:

\begin{equation} \frac{1}{R_{total}} = \frac{1+1+1}{R} \end{equation}

\begin{equation} \frac{1}{R_{total}} = \frac{3}{R} \end{equation}

To find the total resistance ($R_{total}$), we take the reciprocal of both sides of the equation:

\begin{equation} R_{total} = \frac{R}{3} \end{equation}

This result shows that when three equal resistors with resistance $R$ are connected in parallel, the total equivalent resistance is $R$ divided by 3. In other words, the total resistance is one-third of the individual resistance.

Summary of Resistance Calculation

Let's summarize the calculation:

  • Individual resistance of each of the three equal resistors = $R$
  • Connection type = Parallel
  • Formula for parallel resistance: $\frac{1}{R_{total}} = \sum \frac{1}{R_i}$
  • Applying the formula: $\frac{1}{R_{total}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} = \frac{3}{R}$
  • Solving for $R_{total}$: $R_{total} = \frac{R}{3}$

Therefore, the total resistance in the circuit becomes one-third of the individual resistance.

Comparing Parallel vs. Series Resistance

It is helpful to compare this result with resistors connected in series. When resistors $R_1, R_2, R_3, \dots$ are connected in series, the total resistance ($R_{total}$) is simply the sum of the individual resistances:

\begin{equation} R_{total} = R_1 + R_2 + R_3 + \dots \end{equation}

If three equal resistors with resistance $R$ were connected in series, the total resistance would be $R_{total} = R + R + R = 3R$. This is three times the individual resistance.

This comparison highlights a key difference: connecting resistors in parallel decreases the total resistance, while connecting them in series increases the total resistance.

Comparison of Series and Parallel Resistance for Three Equal Resistors (R)
Connection Type Total Resistance Formula Total Resistance for 3 Equal Resistors (R)
Series $R_{total} = R_1 + R_2 + R_3$ $R_{total} = R + R + R = 3R$
Parallel $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$ $R_{total} = \frac{R}{3}$

Revision Table - Electrical Resistance Calculations

Key Concepts for Resistor Connections
Concept Description Formula (n resistors)
Resistors in Series Connected end-to-end, current is the same through each, voltage adds up. Total resistance increases. $R_{total} = R_1 + R_2 + \dots + R_n$
Resistors in Parallel Connected across the same two points, voltage is the same across each, current divides. Total resistance decreases. $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots + \frac{1}{R_n}$
Two Resistors in Parallel A special case for the parallel formula. $R_{total} = \frac{R_1 \times R_2}{R_1 + R_2}$

Additional Information - Factors Affecting Resistance

While this question focuses on how connection type affects total resistance, the resistance of an individual resistor itself depends on several factors:

  • Material: Different materials have different resistivity ($\rho$). Conductors like copper have low resistivity, while insulators have high resistivity.
  • Length: The resistance ($R$) of a conductor is directly proportional to its length ($L$). Longer conductors have higher resistance. $R \propto L$.
  • Cross-sectional Area: The resistance ($R$) of a conductor is inversely proportional to its cross-sectional area ($A$). Thicker conductors have lower resistance. $R \propto \frac{1}{A}$.
  • Temperature: For most conductors, resistance increases with increasing temperature.

These factors are related by the formula for the resistance of a uniform conductor:

\begin{equation} R = \rho \frac{L}{A} \end{equation}

Understanding these factors helps in designing circuits and selecting appropriate components.

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Important Questions from Combination of Resistors — Series and Parallel

  1. Consider two resistors, $R_1$ and $R_2$, connected in series to a DC voltage source. Which of the following statements accurately describes the distribution of current and voltage across these resistors?

  2. A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:

  3. Two bulbs A, of (100w, 100v), and B of (60 w, 100v) are connected in series and across the series combination 200 v is applied. Which bulb will be fused?

  4. 3 resistors of 3 ohm each connected in series. What is the mean values of resistors?

  5. The equivalent resistance of the resistances (two) joined in parallel is 6/5 Ω. When one of the resistance wire is broken, the effective resistance becomes 2Ω. The resistance of the wire that got broken was :

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