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Question

Consider the following grouped frequency distribution :

Class0-1010-2020-3030-4040-5050-60
Frequency124643

What is mean deviation about the median ?

This question was previously asked in
NDA I 2022 GAT Previous Year Paper (10-Apr-2022)
The correct answer is

10.5

Calculating Mean Deviation About Median for Grouped Data

The question asks us to find the mean deviation about the median for the given grouped frequency distribution. 

Understanding Mean Deviation About Median

Mean deviation about the median is a measure of dispersion that calculates the average of the absolute deviations of the observations from the median. For a grouped frequency distribution, the formula is:

\(\text{Mean Deviation (M.D.)} = \frac{\sum_{i=1}^{n} f_i |x_i - \text{Median}|}{\sum_{i=1}^{n} f_i}\)

Where:

  • \(f_i\) is the frequency of the i-th class.
  • \(x_i\) is the midpoint of the i-th class.
  • Median is the median of the distribution.
  • \(\sum f_i\) is the total frequency, also denoted as N.

Step 1: Find the Median

First, we need to find the median of the grouped data. We construct a table with cumulative frequencies.

ClassFrequency (f)Cumulative Frequency (CF)
0-1011
10-2021 + 2 = 3
20-3043 + 4 = 7
30-4067 + 6 = 13
40-50413 + 4 = 17
50-60317 + 3 = 20


 

The total frequency is \(N = \sum f_i = 20\).

We need to find the class containing the \(\left(\frac{N}{2}\right)\)-th observation. \(\frac{N}{2} = \frac{20}{2} = 10\).

The cumulative frequency just greater than or equal to 10 is 13, which corresponds to the class 30-40. So, the median class is 30-40.

Now, we use the formula for the median of a grouped frequency distribution:

\(\text{Median} = L + \frac{\frac{N}{2} - CF}{f} \times h\)

Where:

  • $L$ = Lower limit of the median class = 30
  • $N/2$ = 10
  • $CF$ = Cumulative frequency of the class preceding the median class = 7 (CF of 20-30 class)
  • $f$ = Frequency of the median class = 6 (frequency of 30-40 class)
  • $h$ = Class width = 40 - 30 = 10

Substitute these values into the formula:

\(\text{Median} = 30 + \frac{10 - 7}{6} \times 10\)

\(\text{Median} = 30 + \frac{3}{6} \times 10\)

\(\text{Median} = 30 + 0.5 \times 10\)

\(\text{Median} = 30 + 5\)

\(\text{Median} = 35\)

Step 2: Calculate Mean Deviation About the Median

Now that we have the median (35), we need to calculate the mean deviation about the median. We'll add columns to our table for midpoints (\(x_i\)), absolute deviations from the median (\(|x_i - 35|\)), and the product of frequency and absolute deviation (\(f_i |x_i - 35|\)).

ClassFrequency (f)Midpoint (\(x_i\))\(|x_i - 35|\)\(f_i |x_i - 35|\)
0-101\(\frac{0+10}{2} = 5\)$|5 - 35| = 30$\(1 \times 30 = 30\)
10-202\(\frac{10+20}{2} = 15\)$|15 - 35| = 20$\(2 \times 20 = 40\)
20-304\(\frac{20+30}{2} = 25\)$|25 - 35| = 10$\(4 \times 10 = 40\)
30-406\(\frac{30+40}{2} = 35\)$|35 - 35| = 0$\(6 \times 0 = 0\)
40-504\(\frac{40+50}{2} = 45\)$|45 - 35| = 10$\(4 \times 10 = 40\)
50-603\(\frac{50+60}{2} = 55\)$|55 - 35| = 20$\(3 \times 20 = 60\)


 

Sum of \(f_i |x_i - 35|\) is \(\sum f_i |x_i - 35| = 30 + 40 + 40 + 0 + 40 + 60 = 210\).

Total frequency \(N = \sum f_i = 20\).

Now, calculate the Mean Deviation about the Median:

\(\text{M.D.} = \frac{\sum f_i |x_i - \text{Median}|}{N} = \frac{210}{20}\)

\(\text{M.D.} = 10.5\)

Conclusion

The mean deviation about the median for the given grouped frequency distribution is 10.5.

Revision Table: Mean Deviation Concepts

ConceptDescriptionFormula (Grouped Data)
Mean DeviationAverage of absolute deviations from a central value (Mean or Median).\(\frac{\sum f_i |x_i - A|}{N}\) where A is Mean or Median
Median (Grouped)The middle value; divides the data into two equal halves.\(L + \frac{\frac{N}{2} - CF}{f} \times h\)
Midpoint (\(x_i\))Average of the lower and upper limits of a class.\(\frac{\text{Lower Limit} + \text{Upper Limit}}{2}\)


 

Additional Information on Measures of Dispersion

Mean deviation is a measure of dispersion, which tells us how spread out the data is. Other common measures of dispersion include range, quartile deviation, variance, and standard deviation.

  • Range: The difference between the highest and lowest values in the dataset.
  • Quartile Deviation: Half of the difference between the third quartile (Q3) and the first quartile (Q1).
  • Variance: The average of the squared differences from the mean. It gives more weight to larger deviations.
  • Standard Deviation: The square root of the variance. It is the most commonly used measure of dispersion as it is in the same units as the data.

Mean deviation is less commonly used compared to standard deviation because it uses absolute values, which can be difficult to handle in further mathematical calculations.

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