The observations 4, 1, 4, 3, 6, 2, 1, 3, 4, 5, 1, 6 are outputs of 12 dices thrown simultaneously. If m and M are means of lowest 8 observations and highest 4 observations respectively, then what is (2m + M) equal to ?
10
The problem provides a set of 12 observations, which are the results of throwing 12 dice simultaneously. We are asked to find the mean of the lowest 8 observations (denoted by 'm') and the mean of the highest 4 observations (denoted by 'M'), and then calculate the value of $2m + M$.
To identify the lowest 8 and highest 4 observations, we first need to sort the given data in ascending order.
The given observations are: 4, 1, 4, 3, 6, 2, 1, 3, 4, 5, 1, 6.
Let's list the observations:
Sorting these observations in ascending order, we get:
The lowest 8 observations from the sorted list are the first 8 values:
1, 1, 1, 2, 3, 3, 4, 4
The mean 'm' of these 8 observations is the sum of these observations divided by the number of observations (8).
Sum of lowest 8 observations $= 1 + 1 + 1 + 2 + 3 + 3 + 4 + 4 = 19$
Number of lowest observations $= 8$
Mean $m = \frac{\text{Sum of lowest 8 observations}}{\text{Number of lowest observations}}$
Using the formula for mean:
$\qquad m = \frac{19}{8}$
The highest 4 observations from the sorted list are the last 4 values:
4, 5, 6, 6
The mean 'M' of these 4 observations is the sum of these observations divided by the number of observations (4).
Sum of highest 4 observations $= 4 + 5 + 6 + 6 = 21$
Number of highest observations $= 4$
Mean $M = \frac{\text{Sum of highest 4 observations}}{\text{Number of highest observations}}$
Using the formula for mean:
$\qquad M = \frac{21}{4}$
Now, we need to calculate the value of the expression $2m + M$. We have the values for m and M.
$m = \frac{19}{8}$
$M = \frac{21}{4}$
Let's substitute these values into the expression:
$2m + M = 2 \times \left(\frac{19}{8}\right) + \frac{21}{4}$
First, calculate $2m$:
$2 \times \frac{19}{8} = \frac{2 \times 19}{8} = \frac{38}{8} = \frac{19}{4}$
Now, substitute this back into the expression $2m + M$:
$2m + M = \frac{19}{4} + \frac{21}{4}$
Since the fractions have a common denominator (4), we can simply add the numerators:
$2m + M = \frac{19 + 21}{4} = \frac{40}{4}$
Finally, simplify the fraction:
$2m + M = 10$
So, the value of $(2m + M)$ is 10.
| Concept | Explanation | Application in this problem |
|---|---|---|
| Observation | A data point collected during a study or experiment. | The results from each of the 12 dice throws are observations. |
| Sorting Data | Arranging data points in a specific order, usually ascending or descending. | Necessary to identify the lowest and highest values easily. |
| Mean (Average) | The sum of a set of data points divided by the number of data points. Formula: $\text{Mean} = \frac{\sum x}{n}$. | Used to calculate 'm' (mean of lowest 8) and 'M' (mean of highest 4). |
| Algebraic Expression | A mathematical phrase that can contain numbers, variables, and operators. | The expression $2m + M$ needed to be evaluated after finding m and M. |
Analyzing data often begins with organizing it. Sorting, as done in this problem, helps in quickly identifying minimum, maximum, and ranges of values. Measures of central tendency like the mean, median, and mode provide a single value that represents the center of the data distribution. The mean is sensitive to extreme values, while the median (the middle value of sorted data) is not.
In problems involving subsets of data, like the lowest or highest values, sorting is a crucial first step before applying statistical calculations. Understanding how to perform basic operations like sorting and calculating means is fundamental in statistics and data analysis.
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