Consider the following grouped frequency distribution :Class 0-10 10-20 20-30 30-40 40-50 50-60 Frequency 1 2 4 6 4 3
What is the median of the distribution ?
35
The question asks us to find the median of the given grouped frequency distribution. The median is the middle value in a dataset that is ordered from least to greatest. For grouped data, we first need to find the median class and then use a specific formula to calculate the exact median value within that class.
Here is the provided distribution:
| Class | Frequency (f) |
|---|---|
| 0-10 | 1 |
| 10-20 | 2 |
| 20-30 | 4 |
| 30-40 | 6 |
| 40-50 | 4 |
| 50-60 | 3 |
To calculate the median for this grouped frequency distribution, we follow these steps:
\( \text{Median} = L + \left( \frac{\frac{N}{2} - C}{f} \right) \times h \)
Where:Let's apply the steps to our frequency distribution.
1. Total frequency \( N \):
\( N = 1 + 2 + 4 + 6 + 4 + 3 = 20 \)
2. Calculate \( \frac{N}{2} \):
\( \frac{N}{2} = \frac{20}{2} = 10 \)
The median is the value corresponding to the 10th observation.
3. Create the cumulative frequency column:
| Class | Frequency (f) | Cumulative Frequency (CF) |
|---|---|---|
| 0-10 | 1 | 1 |
| 10-20 | 2 | 1 + 2 = 3 |
| 20-30 | 4 | 3 + 4 = 7 |
| 30-40 | 6 | 7 + 6 = 13 |
| 40-50 | 4 | 13 + 4 = 17 |
| 50-60 | 3 | 17 + 3 = 20 |
4. Identify the median class: The first cumulative frequency greater than or equal to 10 is 13, which falls in the class interval 30-40. Therefore, the median class is 30-40.
5. Identify the values for the formula from the median class (30-40):
6. Apply the formula:
\( \text{Median} = L + \left( \frac{\frac{N}{2} - C}{f} \right) \times h \)
\( \text{Median} = 30 + \left( \frac{10 - 7}{6} \right) \times 10 \)
\( \text{Median} = 30 + \left( \frac{3}{6} \right) \times 10 \)
\( \text{Median} = 30 + \left( 0.5 \right) \times 10 \)
\( \text{Median} = 30 + 5 \)
\( \text{Median} = 35 \)
Thus, the median of the given grouped frequency distribution is 35.
| Concept | Description | Key Formula/Method |
|---|---|---|
| Median Definition (Grouped Data) | The middle value of the distribution, estimated within a specific class interval. | Locate median class (\( \frac{N}{2} \)). |
| Median Class | The class interval containing the \( \frac{N}{2} \)-th observation. Identified using cumulative frequency. | CF \( \ge \frac{N}{2} \) for the first time. |
| Median Formula | Formula used to calculate the median value within the median class. | \( L + \left( \frac{\frac{N}{2} - C}{f} \right) \times h \) |
| Cumulative Frequency (CF) | Running total of frequencies up to a particular class. | Sum of frequency of current class and all previous frequencies. |
| Class Size (h) | The width of a class interval. | Upper limit - Lower limit (for exclusive classes). |
The median is one of the main measures of central tendency, which are used to describe the center of a dataset. Other common measures include the mean and the mode.
Choosing the appropriate measure of central tendency depends on the type of data and the distribution's shape. For skewed distributions, the median is often preferred over the mean as a representative center.
What is mean deviation about the median ?
The observations 4, 1, 4, 3, 6, 2, 1, 3, 4, 5, 1, 6 are outputs of 12 dices thrown simultaneously. If m and M are means of lowest 8 observations and highest 4 observations respectively, then what is (2m + M) equal to ?
The frequency curve (assuming unimodal) corresponding to the data obtained in an experiment is skewed to the left. What conclusion can be drawn from the curve ?
What is the mean of the marks ?
What is the median of the marks?
What is the sum of the deviations measured from the median?
If the frequency of each class is doubled, then what would be the mean?
What is the value of p ?
What is the value of q ?
What is mean deviation about the median ?
The mode and median of a data is 26.7 and 71, respectively. What is the mean of the data? (Use empirical formula.)
Study the given table and answer the question that follows. The given table depicts the percentage of marks scored by Mary and Perul in History and Physics (out of 75 each).
| Name | History | Physics |
|---|---|---|
Mary | 60 | 64 |
Perul | 54 | 70 |
How many marks did Mary score in History?
The average of eight numbers is 14. The average of six of these numbers is 16. The average of the remaining two numbers is:
The value of
(1 + cot²θ)(1 + cosθ)(1 - cosθ) - (1 - sinθ)(1 + sinθ)(1 + tan²θ) is: (θ lies in the first quadrant)