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Question

Two resistors, each of \(20\ \Omega\), are connected in parallel, and this combination is connected across a 40-V supply. Find the voltage across each resistor.

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
40 V

Parallel Resistor Voltage Analysis

Key Principle for Parallel Circuits:

  • When components are connected in parallel, the voltage across each component is identical to the voltage across the source supplying them.
  • This is a fundamental property of parallel electrical connections.

Problem Details:

  • The resistors are connected in parallel.
  • The supply voltage (\(V_{supply}\)) is given as \(40\ \text{V}\).
  • Each resistor has a resistance (\(R\)) of \(20\ \Omega\).

Voltage Calculation:

  • Because the two \(20\ \Omega\) resistors are connected in parallel across the \(40\ \text{V}\) supply, the voltage drop across each individual resistor (\(V_R\)) must be equal to the supply voltage.
  • Thus, the voltage across each resistor is \(V_R = V_{supply}\).
  • \(V_R = 40\ \text{V}\).

Conclusion:

  • The voltage across each of the \(20\ \Omega\) resistors is \(40\ \text{V}\).
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Important Questions from Combination of Resistors — Series and Parallel

  1. Consider two resistors, $R_1$ and $R_2$, connected in series to a DC voltage source. Which of the following statements accurately describes the distribution of current and voltage across these resistors?

  2. A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:

  3. Two bulbs A, of (100w, 100v), and B of (60 w, 100v) are connected in series and across the series combination 200 v is applied. Which bulb will be fused?

  4. 3 resistors of 3 ohm each connected in series. What is the mean values of resistors?

  5. The equivalent resistance of the resistances (two) joined in parallel is 6/5 Ω. When one of the resistance wire is broken, the effective resistance becomes 2Ω. The resistance of the wire that got broken was :

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