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Question

Power of a lens of focal length 'f' is directly proportional to __________.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is
$1/f$

Lens Power Directly Proportional to Focal Length

The question asks about the relationship between the power of a lens and its focal length. Let's explore this concept.

Understanding Lens Power

In optics, the power of a lens is a measure of how strongly it converges or diverges light. It is defined as the reciprocal of the focal length of the lens.

The Formula for Lens Power

The mathematical relationship between the power (\(P\)) of a lens and its focal length (\(f\)) is given by the formula:

$P = \frac{1}{f}

Where:

  • \(P\) is the power of the lens, measured in diopters (D).
  • \(f\) is the focal length of the lens, measured in meters (m).

It's important that the focal length is in meters for the power to be in diopters. If the focal length is given in centimeters, it must be converted to meters before calculating the power.

Direct Proportionality Explained

Two quantities are directly proportional if they change by the same factor. If quantity A is directly proportional to quantity B, it means that as B increases, A increases proportionally, and as B decreases, A decreases proportionally. Mathematically, this is represented as \(A \propto B\).

Looking at the formula \(P = \frac{1}{f}\), we can see how the power (\(P\)) relates to the focal length (\(f\)).

  • If the focal length (\(f\)) increases, the value of \(\frac{1}{f}\) decreases.
  • If the focal length (\(f\)) decreases, the value of \(\frac{1}{f}\) increases.

Therefore, the power (\(P\)) is directly proportional to the term \(\frac{1}{f}\). This can be written as:

$P \propto \frac{1}{f}

Conclusion

Based on the definition and the formula \(P = \frac{1}{f}\), the power of a lens is directly proportional to the reciprocal of its focal length (\(\frac{1}{f}\)).

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