Keeping voltage constant, if more lamps are put into a series circuit, the overall current in the circuit: A. Increases B. Decreases C. Remains the same D. Becomes infinite
B
This question explores a fundamental concept in electrical circuits, specifically how adding components in a series circuit affects the overall current when the voltage is kept constant. It relies on Ohm's Law, which describes the relationship between voltage, current, and resistance.
In an electrical circuit, lamps act as resistors because they impede the flow of electric current. When multiple components, like lamps, are connected in series, their resistances add up.
So, adding more lamps in series increases the total resistance of the circuit.
Ohm's Law states the relationship between Voltage (V), Current (I), and Resistance (R) as:
$$V = I \times R$$
This can be rearranged to find the current:
$$I = \frac{V}{R}$$
The question states that the voltage (V) is kept constant. We have established that adding more lamps in series increases the total resistance ($R_{total}$). Let's see how this affects the current (I) using Ohm's Law:
Keeping the voltage constant, if more lamps are put into a series circuit, the total resistance of the circuit increases. According to Ohm's Law ($I = V/R$), if the voltage stays the same and the resistance increases, the current must decrease.
| Parameter | Behavior in Series Circuit |
| Current (I) | Same at all points in the circuit. |
| Voltage (V) | Total voltage across the circuit is the sum of voltages across each component ($V_{total} = V_1 + V_2 + \dots$). |
| Resistance (R) | Total resistance is the sum of individual resistances ($R_{total} = R_1 + R_2 + \dots$). |
It's helpful to compare this behavior to a parallel circuit:
Understanding the difference between series and parallel circuits is key to solving many electrical problems.
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