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Question

Two resistors 1 ohm and 2 ohm are connected in series. The effective resistance is

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
3 ohm

Calculating Series Resistance

When resistors are connected in series, their resistances add up to find the total or effective resistance of the circuit.

Series Resistance Formula

The formula for calculating the effective resistance (\(R_{total}\)) of resistors connected in series is:

\(R_{total} = R_1 + R_2 + \dots + R_n\)

Where \(R_1, R_2, \dots, R_n\) are the individual resistances.

Applying the Formula

Given:

  • Resistor 1 (\(R_1\)): 1 ohm
  • Resistor 2 (\(R_2\)): 2 ohm

Substitute the values into the series resistance formula:

\(R_{total} = 1 \, \text{ohm} + 2 \, \text{ohm}\)

\(R_{total} = 3 \, \text{ohm}\)

Result

The effective resistance of the 1 ohm and 2 ohm resistors connected in series is 3 ohm.

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Important Questions from Combination of Resistors — Series and Parallel

  1. Consider two resistors, $R_1$ and $R_2$, connected in series to a DC voltage source. Which of the following statements accurately describes the distribution of current and voltage across these resistors?

  2. A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:

  3. Two bulbs A, of (100w, 100v), and B of (60 w, 100v) are connected in series and across the series combination 200 v is applied. Which bulb will be fused?

  4. 3 resistors of 3 ohm each connected in series. What is the mean values of resistors?

  5. The equivalent resistance of the resistances (two) joined in parallel is 6/5 Ω. When one of the resistance wire is broken, the effective resistance becomes 2Ω. The resistance of the wire that got broken was :

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