Calculating Series Resistance
When resistors are connected in series, their resistances add up to find the total or effective resistance of the circuit.
Series Resistance Formula
The formula for calculating the effective resistance (\(R_{total}\)) of resistors connected in series is:
\(R_{total} = R_1 + R_2 + \dots + R_n\)
Where \(R_1, R_2, \dots, R_n\) are the individual resistances.
Applying the Formula
Given:
- Resistor 1 (\(R_1\)): 1 ohm
- Resistor 2 (\(R_2\)): 2 ohm
Substitute the values into the series resistance formula:
\(R_{total} = 1 \, \text{ohm} + 2 \, \text{ohm}\)
\(R_{total} = 3 \, \text{ohm}\)
Result
The effective resistance of the 1 ohm and 2 ohm resistors connected in series is 3 ohm.
Similar Questions
- Two resistors, one of \(20\ \Omega\) and the other of \(30\ \Omega\), are connected in parallel. This combination is connected in series with an \(8\ \Omega\) resistor and a 12-V battery. The current through the \(20\ \Omega\) resistor is:
- Two resistors, each of \(20\ \Omega\), are connected in parallel, and this combination is connected across a 40-V supply. Find the voltage across each resistor.
- Two \(100\text{-}\Omega\) resistors are connected in parallel, and this combination is connected across a 40-V supply. Find the current supplied by the voltage source.
- Two resistors, each of \(10\ \Omega\), are connected in parallel. This combination is then connected in series with a third \(10\ \Omega\) resistor and a 6 V battery. The current in the circuit is ______.
- Two resistors, one of \(8\ \Omega\) and the other of \(24\ \Omega\) are connected in parallel. This combination is connected in series with a \(14\ \Omega\) resistor and a 12 V battery. The current in the \(8\ \Omega\) resistor is:
- Two resistors, A and B are connected in parallel combination in an electric circuit as to have an equivalent resistance of \(3\,\Omega\). On connecting the resistors A and B in series combination the equivalent resistant is found to be \(12\,\Omega\). Then the resistance R1 and R2 of the two resistors A and B respectively could be
- Two resistors, one of \(20\ \Omega\) and the other of \(30\ \Omega\), are connected in parallel. This combination is connected in series with an \(8\ \Omega\) resistor and a 12-V battery. The current through the \(20\ \Omega\) resistor is:
- Two resistors, each of \(20\ \Omega\), are connected in parallel, and this combination is connected across a 40-V supply. Find the voltage across each resistor.
- Two \(100\ \Omega\) resistors are connected in parallel, and this combination is connected across a 40-V supply. Find the current supplied by the voltage source.
Important Questions from Combination of Resistors — Series and Parallel
A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:
3 resistors of 3 ohm each connected in series. What is the mean values of resistors?
Ten cells, each of 2 volts emf and 1 ohm internal resistance are connected in series. What is the current flowing through a resistance of 10 ohms connected across this combination of cells?
Three resistor, each equal to 3 Ω are connected so as to form a triangle. The equivalent resistance between any two vertices of the triangle is:
- Two resistors R 1 and R 2 arranged in parallel combination in an electrical closed circuit are made of the same material and of the same thickness. If the length of R 2 is twice the length of R 1, then the total resistance R satisfies
