Calculating Series Resistance
When resistors are connected in series, their resistances add up to find the total or effective resistance of the circuit.
The formula for calculating the effective resistance (\(R_{total}\)) of resistors connected in series is:
\(R_{total} = R_1 + R_2 + \dots + R_n\)
Where \(R_1, R_2, \dots, R_n\) are the individual resistances.
Given:
Substitute the values into the series resistance formula:
\(R_{total} = 1 \, \text{ohm} + 2 \, \text{ohm}\)
\(R_{total} = 3 \, \text{ohm}\)
The effective resistance of the 1 ohm and 2 ohm resistors connected in series is 3 ohm.
Consider two resistors, $R_1$ and $R_2$, connected in series to a DC voltage source. Which of the following statements accurately describes the distribution of current and voltage across these resistors?
A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:
Two bulbs A, of (100w, 100v), and B of (60 w, 100v) are connected in series and across the series combination 200 v is applied. Which bulb will be fused?
3 resistors of 3 ohm each connected in series. What is the mean values of resistors?
The equivalent resistance of the resistances (two) joined in parallel is 6/5 Ω. When one of the resistance wire is broken, the effective resistance becomes 2Ω. The resistance of the wire that got broken was :