Parallel Resistor Current Calculation
The problem asks for the total current supplied by the voltage source when two resistors are connected in parallel across it.
Identify Given Values
- Resistance of each resistor, \(R_1 = R_2 = 100\ \Omega\).
- Voltage supply, \(V = 40\ V\).
Calculate Equivalent Resistance
For resistors in parallel, the equivalent resistance (\(R_{eq}\)) is calculated using the formula:
\( \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} \)
Substituting the values:
\( \frac{1}{R_{eq}} = \frac{1}{100\ \Omega} + \frac{1}{100\ \Omega} = \frac{2}{100\ \Omega} \)
Therefore, the equivalent resistance is:
\( R_{eq} = \frac{100\ \Omega}{2} = 50\ \Omega \)
Calculate Total Current
Using Ohm's Law, the total current (\(I\)) supplied by the voltage source is:
\( I = \frac{V}{R_{eq}} \)
Substituting the values:
\( I = \frac{40\ V}{50\ \Omega} \)
\( I = 0.8\ A \)
Conclusion
The current supplied by the voltage source is 0.8 A.
Similar Questions
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Important Questions from Combination of Resistors — Series and Parallel
A cell of negligible resistance and e.m.f 2 volt is connected to series combination of 2 ohm, 3 ohm and 5 ohm. The potential difference across the 3 ohm resistance is:
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Three resistor, each equal to 3 Ω are connected so as to form a triangle. The equivalent resistance between any two vertices of the triangle is:
- Two resistors R 1 and R 2 arranged in parallel combination in an electrical closed circuit are made of the same material and of the same thickness. If the length of R 2 is twice the length of R 1, then the total resistance R satisfies
