All Exams Test series for 1 year @ ₹349 only
Question

The volume of a solid hemisphere is 19,404 cm 3. Its total surface area (in cm 2) is:

(Take π =  \(\frac{{ {22} }}{7}\) )

This question was previously asked in
SSC CGL 2020 Tier-II (English) Previous Year Paper (29-Jan-2022)
The correct answer is

4158

Finding the Total Surface Area of a Solid Hemisphere from its Volume

The problem asks us to find the total surface area of a solid hemisphere given its volume. We are provided with the volume and asked to use the value of \(\pi\) as \(\frac{22}{7}\).

Given Information

  • Volume of the solid hemisphere = 19,404 cm³
  • Value of \(\pi\) to use = \(\frac{22}{7}\)

Finding the Radius of the Hemisphere

The formula for the volume of a solid hemisphere is given by:

\(V = \frac{2}{3} \pi r^3\)

Where \(V\) is the volume and \(r\) is the radius of the hemisphere.

We are given \(V = 19404 \text{ cm}^3\). Substituting the given values into the formula:

\(19404 = \frac{2}{3} \times \frac{22}{7} \times r^3\)

\(19404 = \frac{44}{21} r^3\)

To find \(r^3\), we can rearrange the equation:

\(r^3 = 19404 \times \frac{21}{44}\)

Let's perform the division of 19404 by 44:

\(19404 \div 44\)

We can divide both by 4 first: \(19404 \div 4 = 4851\), and \(44 \div 4 = 11\). So we have \(4851 \div 11\).

\(4851 \div 11 = 441\)

So, the equation becomes:

\(r^3 = 441 \times 21\)

We know that \(441 = 21^2\). So,

\(r^3 = 21^2 \times 21\)

\(r^3 = 21^3\)

Taking the cube root of both sides:

\(r = 21 \text{ cm}\)

The radius of the solid hemisphere is 21 cm.

Calculating the Total Surface Area

The total surface area of a solid hemisphere includes both the curved surface area and the area of the circular base. The formula for the total surface area (TSA) is:

\(TSA = 3 \pi r^2\)

Where \(r\) is the radius we just found (21 cm) and \(\pi = \frac{22}{7}\).

Substitute the values into the formula:

\(TSA = 3 \times \frac{22}{7} \times (21)^2\)

\(TSA = 3 \times \frac{22}{7} \times 441\)

Divide 441 by 7:

\(441 \div 7 = 63\)

So, the calculation becomes:

\(TSA = 3 \times 22 \times 63\)

\(TSA = 66 \times 63\)

Now, multiply 66 by 63:

\(66 \times 63 = 4158\)

The total surface area of the solid hemisphere is 4158 cm².

Summary of Steps

  1. Use the given volume of the solid hemisphere and the formula \(V = \frac{2}{3} \pi r^3\) to find the radius \(r\).
  2. Substitute the calculated radius \(r\) into the formula for the total surface area of a solid hemisphere, \(TSA = 3 \pi r^2\).
  3. Calculate the final value of the total surface area.
Calculation Summary
Quantity Formula/Value Calculation Result
Volume (V) Given 19404 cm³
Volume Formula \( \frac{2}{3} \pi r^3 \)
Radius (r) Derived from Volume \( r^3 = \frac{3 \times 19404}{2 \times \frac{22}{7}} = 19404 \times \frac{21}{44} = 441 \times 21 = 21^3 \) 21 cm
Total Surface Area (TSA) Formula \( 3 \pi r^2 \)
TSA Value \( 3 \times \frac{22}{7} \times (21)^2 \) \( 3 \times \frac{22}{7} \times 441 = 3 \times 22 \times 63 \) 4158 cm²

Revision Table: Hemisphere Formulas

Important Formulas for Hemisphere
Property Formula Notes
Volume of Hemisphere \( V = \frac{2}{3} \pi r^3 \) Half the volume of a sphere
Curved Surface Area (CSA) of Hemisphere \( CSA = 2 \pi r^2 \) Half the surface area of a sphere
Base Area of Hemisphere \( A_{\text{base}} = \pi r^2 \) Area of the circular base
Total Surface Area (TSA) of Solid Hemisphere \( TSA = 3 \pi r^2 \) CSA + Base Area

Additional Information on Hemispheres and Surface Area

A hemisphere is exactly half of a sphere. When we talk about the surface area of a hemisphere, it's important to distinguish between the curved surface area and the total surface area, especially if it's a solid object.

  • Curved Surface Area: This is the area of the rounded part only. For a hemisphere, this is half the surface area of the full sphere, which is \(2 \pi r^2\).
  • Total Surface Area: For a *solid* hemisphere, this includes the curved surface area plus the area of the flat circular base. The base is a circle with radius \(r\), so its area is \(\pi r^2\). Thus, the total surface area of a solid hemisphere is \(2 \pi r^2 + \pi r^2 = 3 \pi r^2\). If the hemisphere is hollow (like a bowl without a lid), its total surface area might just be the curved surface area, or it could include the area of a thin rim, depending on the specific definition in a problem. In this question, it specifies a "solid hemisphere", so we must include the base area.
  • Volume: The volume of a hemisphere is always half the volume of the corresponding sphere. The volume of a sphere is \(\frac{4}{3} \pi r^3\), so the volume of a hemisphere is \(\frac{1}{2} \times \frac{4}{3} \pi r^3 = \frac{2}{3} \pi r^3\). This formula applies whether the hemisphere is solid or hollow (as long as we're calculating the space it occupies).

Understanding these distinct formulas is crucial for solving problems involving hemispheres in geometry and mensuration.

Was this answer helpful?

Similar Questions

  1. If the total surface area of a cube is 24 sq.units, then what is the volume of the cube?

  2. The volume of a cone is 73920 cm3. If the height of the cone is 160 cm, then find the diameter of its base.

  3. Ranu carries water to school in a cylindrical flask with diameter 12 cm and height 21 cm. Determine the amount of water that she can carry in the flask. (Use π = \(\frac{22}{7}\))

  4. The volume of a cone with height equal to radius, and slant height 5 cm is :

  5. What is the whole surface area of a cone of base radius 6 cm and height 8 cm?

  6. What is the volume of a cube if the perimeter of one face of the cube is 40 cm?

  7. A spherical ball of lead, 3 cm in diameter, is melted and recast into three spherical balls. The diameters of two of these balls are \(\frac{3}{2}\) cm and 2 cm, respectively. Find the diameter of the third ball.  

  8. A conical tent of height 10 m and base diameter 48 m was erected by a company in a park. Find the curved surface area of the tent (In m2).

  9. If the surface area of a cube is 5046 cm2, then the volume of the cube is:

  10. The volume of a cuboid is twice that of a cube. If the dimensions of the cuboid are (8 m × 8 m ×16 m), the total surface area of the cube is: 


Important Questions from Solid Figures

  1. The area of the floor of a cubical room is 192 m 2. The length of the longest rod that can be kept in that room is :

  2. A solid metallic rectangular block of dimensions 112 cm × 44 cm × 25 cm is melted and recast into a cylinder of radius 35 cm. The curved surface area (in cm 2) of the cylinder is: (Take π = 22/7)

  3. If the volume of a cube is 175616 cm 3, what is its side?

  4. The volume of a right circular cone is 1232 cm 3. If the height of the cone is 24 cm, then what will be the radius of its base?

  5. A right triangle contains the right angle between the sides 5 cm and 7 cm. A cone is generated by revolving about the side 5 cm. The volume of this cone is:

Need Expert Advice?
Upcoming Exams
SSC JHT
September 08, 2026
SSC Stenographer
September 09, 2026
SSC Selection Post
September 16, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2500 Tests 6 Tests Free
3990 Attempts
4.2(838)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App