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Question

What will be the total cost (in Rs.) of polishing the curved surface of a wooden cylinder at rate of Rs. 50 per m 2, if its diameter is 70 cm and height is 6 m? (Take π =  \(\frac{22}{7}\) )

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

660

Calculating the Cost of Polishing a Cylinder's Curved Surface

The problem asks us to find the total cost of polishing the curved surface of a wooden cylinder. We are given the dimensions of the cylinder and the rate at which the polishing is done per square meter.

Understanding the Given Information

  • Shape to be polished: Curved surface of a cylinder.
  • Diameter of the cylinder: 70 cm.
  • Height of the cylinder: 6 m.
  • Polishing rate: Rs. 50 per m2.
  • Value of π to use: \(\frac{22}{7}\).

Step 1: Ensure Units are Consistent

The polishing rate is given in Rupees per square meter (m2), but the diameter is given in centimeters (cm). We need to convert the diameter into meters so that all measurements are in the same unit (meters).

Diameter = 70 cm

Since 1 m = 100 cm, we convert cm to meters by dividing by 100.

Diameter in meters = \(\frac{70}{100}\) m = 0.70 m

The height is already in meters.

Height (h) = 6 m

Step 2: Find the Radius of the Cylinder

The radius of a cylinder is half of its diameter.

Radius (r) = \(\frac{\text{Diameter}}{2}\)

Radius (r) = \(\frac{0.70 \text{ m}}{2}\) = 0.35 m

Step 3: Calculate the Curved Surface Area (CSA) of the Cylinder

The area to be polished is the curved surface area of the cylinder. The formula for the curved surface area of a cylinder is:

CSA = \(2 \pi r h\)

Substitute the values of π, r, and h into the formula:

CSA = \(2 \times \frac{22}{7} \times 0.35 \text{ m} \times 6 \text{ m}\)

Let's simplify the calculation:

CSA = \(2 \times \frac{22}{7} \times \frac{35}{100} \times 6\) m2

We can simplify \(\frac{35}{7}\) to 5:

CSA = \(2 \times 22 \times \frac{5}{100} \times 6\) m2

Now simplify \(\frac{5}{100}\) to \(\frac{1}{20}\):

CSA = \(2 \times 22 \times \frac{1}{20} \times 6\) m2

Simplify \(2 \times \frac{1}{20}\) to \(\frac{1}{10}\):

CSA = \(22 \times \frac{1}{10} \times 6\) m2

CSA = \(22 \times 0.1 \times 6\) m2

CSA = \(2.2 \times 6\) m2

CSA = 13.2 m2

So, the curved surface area of the wooden cylinder is 13.2 square meters.

Step 4: Calculate the Total Cost of Polishing

The cost of polishing is Rs. 50 per square meter. To find the total cost, we multiply the curved surface area by the polishing rate.

Total Cost = Curved Surface Area \(\times\) Rate per m2

Total Cost = \(13.2 \text{ m}^2 \times 50 \text{ Rs./m}^2\)

Total Cost = \(13.2 \times 50\) Rs.

Total Cost = \(132 \times 5\) Rs. (multiplying 13.2 by 10 and dividing 50 by 10)

Total Cost = 660 Rs.

Conclusion

The total cost of polishing the curved surface of the wooden cylinder is Rs. 660.

Measurement Value Unit (converted)
Diameter 70 cm 0.7 m
Radius (r) 0.35 m 0.35 m
Height (h) 6 m 6 m
Rate 50 Rs./m2

Revision Table: Cylinder Surface Area & Cost Calculation

Concept Formula Application
Radius from Diameter \(r = \frac{d}{2}\) Convert diameter unit, then divide by 2.
Curved Surface Area (CSA) of Cylinder \(2\pi r h\) Area of the side face.
Total Surface Area (TSA) of Cylinder \(2\pi r (r+h)\) CSA + Area of two circular bases.
Cost Calculation Area \(\times\) Rate Ensure area and rate units match.

Additional Information: Properties of a Cylinder

A cylinder is a 3D shape with two parallel circular bases connected by a curved surface. Key properties include:

  • It has three faces: the top circular base, the bottom circular base, and the curved lateral surface.
  • It has two edges, which are the circumferences of the circular bases.
  • It has no vertices (corners).
  • The height is the perpendicular distance between the two bases.
  • The radius is the radius of the circular bases.

Calculating surface areas and volumes of cylinders is a common topic in mensuration, which deals with the measurement of geometric shapes.

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Similar Questions

  1. The curved surface area and the volume of a cylindrical object are 88 cm 2and 132 cm 3, respectively. The height (in cm) of the cylindrical object is:

    (Take π =   \(\frac{{22}}{7}\) )

  2. The circumference of the base of a cylindrical vessel is 264 cm and its height is 50 cm. The capacity (in litres) of the vessel is:

    (Take π =  \(\frac{22}{7}\) )

  3. A cylindrical tube, open at both ends, is made of a metal sheet which is 0.5 cm thick. Its outer radius is 4 cm and length is 2 m. How much metal (in cm 3) has been used in making the tube?

  4. The volume of a right circular cone is 308 cm 3 and the radius of its base is 7 cm. What is the curved surface area (in cm 2) of the cone? (Take π =  \(\frac{22}{7} \) )

  5. The slant height and radius of a right circular cone are in the ratio 29 ∶ 20. If its volume is 4838.4 π cm 3, then its radius is: 

  6. Six cubes, each of edge 2 cm, are joined end to end. What is the total surface area of the resulting cuboid in cm 2?

  7. Find the total surface area of a cube whose volume is 343 m3.

  8. A solid metallic sphere of radius 12 cm is melted and recast into a cone having diameter of the base as 12 cm. What is the height of the cone?

  9. The expenditure on the cost of living of a man and his family is 60% of his salary. He gets two increment of 30% and 60% in his salary. If his saving increases by 250% of his initial saving, then the new cost of living expenditure is what percentage (rounded off to the nearest integer) of the increased salary?

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Important Questions from Solid Figures

  1. A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?

  2. A cube is 7 cm of an edge and another cube is 14 cm on an edge. The ratios of their surface areas are

  3. Using three distinct points which of the following shapes cannot be formed?

  4. Two cubes each of edge 12 cm are joined end to end. Find the surface area of the resulting cuboid.

  5. The areas of three adjacent faces of a cuboid are x, y, z. If the volume is V, then V 2will be equal to:

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