What will be the total cost (in Rs.) of polishing the curved surface of a wooden cylinder at rate of Rs. 50 per m 2, if its diameter is 70 cm and height is 6 m? (Take π = \(\frac{22}{7}\) )
660
The problem asks us to find the total cost of polishing the curved surface of a wooden cylinder. We are given the dimensions of the cylinder and the rate at which the polishing is done per square meter.
The polishing rate is given in Rupees per square meter (m2), but the diameter is given in centimeters (cm). We need to convert the diameter into meters so that all measurements are in the same unit (meters).
Diameter = 70 cm
Since 1 m = 100 cm, we convert cm to meters by dividing by 100.
Diameter in meters = \(\frac{70}{100}\) m = 0.70 m
The height is already in meters.
Height (h) = 6 m
The radius of a cylinder is half of its diameter.
Radius (r) = \(\frac{\text{Diameter}}{2}\)
Radius (r) = \(\frac{0.70 \text{ m}}{2}\) = 0.35 m
The area to be polished is the curved surface area of the cylinder. The formula for the curved surface area of a cylinder is:
CSA = \(2 \pi r h\)
Substitute the values of π, r, and h into the formula:
CSA = \(2 \times \frac{22}{7} \times 0.35 \text{ m} \times 6 \text{ m}\)
Let's simplify the calculation:
CSA = \(2 \times \frac{22}{7} \times \frac{35}{100} \times 6\) m2
We can simplify \(\frac{35}{7}\) to 5:
CSA = \(2 \times 22 \times \frac{5}{100} \times 6\) m2
Now simplify \(\frac{5}{100}\) to \(\frac{1}{20}\):
CSA = \(2 \times 22 \times \frac{1}{20} \times 6\) m2
Simplify \(2 \times \frac{1}{20}\) to \(\frac{1}{10}\):
CSA = \(22 \times \frac{1}{10} \times 6\) m2
CSA = \(22 \times 0.1 \times 6\) m2
CSA = \(2.2 \times 6\) m2
CSA = 13.2 m2
So, the curved surface area of the wooden cylinder is 13.2 square meters.
The cost of polishing is Rs. 50 per square meter. To find the total cost, we multiply the curved surface area by the polishing rate.
Total Cost = Curved Surface Area \(\times\) Rate per m2
Total Cost = \(13.2 \text{ m}^2 \times 50 \text{ Rs./m}^2\)
Total Cost = \(13.2 \times 50\) Rs.
Total Cost = \(132 \times 5\) Rs. (multiplying 13.2 by 10 and dividing 50 by 10)
Total Cost = 660 Rs.
The total cost of polishing the curved surface of the wooden cylinder is Rs. 660.
| Measurement | Value | Unit (converted) |
|---|---|---|
| Diameter | 70 cm | 0.7 m |
| Radius (r) | 0.35 m | 0.35 m |
| Height (h) | 6 m | 6 m |
| Rate | 50 | Rs./m2 |
| Concept | Formula | Application |
|---|---|---|
| Radius from Diameter | \(r = \frac{d}{2}\) | Convert diameter unit, then divide by 2. |
| Curved Surface Area (CSA) of Cylinder | \(2\pi r h\) | Area of the side face. |
| Total Surface Area (TSA) of Cylinder | \(2\pi r (r+h)\) | CSA + Area of two circular bases. |
| Cost Calculation | Area \(\times\) Rate | Ensure area and rate units match. |
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