If the surface area of a sphere is 64 π cm 2, then the volume of the sphere is:
This problem asks us to find the volume of a sphere given its surface area. We need to use the formulas for the surface area and volume of a sphere to solve this.
A sphere is a perfectly round geometrical object in three-dimensional space that is the surface of a perfectly round ball. The key properties related to this problem are its surface area and volume.
We are given that the surface area of the sphere is \(64 \pi \) cm2. We can use this information and the surface area formula to find the radius of the sphere.
We set the given surface area equal to the formula for the surface area:
\(4 \pi r^2 = 64 \pi \)
To find \(r^2\), we divide both sides by \(4 \pi \):
\(r^2 = \frac{64 \pi }{4 \pi }\)
\(r^2 = 16\)
Now, we take the square root of both sides to find the radius \(r\):
\(r = \sqrt{16}\)
\(r = 4\) cm
So, the radius of the sphere is 4 cm.
Now that we have the radius (\(r = 4\) cm), we can use the formula for the volume of a sphere:
\(V = \frac{4}{3} \pi r^3\)
Substitute the value of \(r\) into the formula:
\(V = \frac{4}{3} \pi (4)^3\)
Calculate \(4^3\):
\(4^3 = 4 \times 4 \times 4 = 16 \times 4 = 64\)
Substitute \(64\) back into the volume formula:
\(V = \frac{4}{3} \pi (64)\)
Multiply \(\frac{4}{3}\) by \(64\):
\(V = \frac{4 \times 64}{3} \pi \)
\(V = \frac{256}{3} \pi \)
The volume of the sphere is \(\frac{256}{3} \pi \) cm3.
| Step | Action | Calculation |
|---|---|---|
| 1 | Use surface area to find radius | \(4 \pi r^2 = 64 \pi \implies r^2 = 16 \implies r = 4\) cm |
| 2 | Use radius to find volume | \(V = \frac{4}{3} \pi (4)^3 = \frac{4}{3} \pi (64) = \frac{256}{3} \pi \) cm3 |
Comparing our calculated volume with the given options, we find that it matches option 4.
| Property | Formula | Variables |
|---|---|---|
| Surface Area | \(A = 4 \pi r^2\) | \(A\) = Surface Area, \(r\) = Radius |
| Volume | \(V = \frac{4}{3} \pi r^3\) | \(V\) = Volume, \(r\) = Radius |
| Circumference of Great Circle | \(C = 2 \pi r\) | \(C\) = Circumference, \(r\) = Radius |
A sphere is a fundamental 3D shape. It is defined as the set of all points in three-dimensional space that are equally distant from a given point, called the center. The constant distance is called the radius.
A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?
A metallic solid cuboid of dimensions 36 cm × 18 cm × 12 cm is melted and recast in the form of cubes of side 6 cm. Find the number of cubes so formed.
A solid cylinder has a radius of 9 cm and a height of 25 cm. What is the ratio of its total surface area to its curved surface area?
Find the surface area of a sphere of diameter 21 cm. (Use π = \(\frac{{22}}{7}\) )
A cuboid of dimension 24 cm, 9 cm and 8 cm is melted and smaller cubes of side 3 cm are formed. How many such cubes can be formed?