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Question

If the surface area of a sphere is 64 π cm 2, then the volume of the sphere is:

The correct answer is \(\frac{{256}}{{3}}\pi \) cm3

Calculating Sphere Volume from Surface Area

This problem asks us to find the volume of a sphere given its surface area. We need to use the formulas for the surface area and volume of a sphere to solve this.

Understanding Sphere Formulas

A sphere is a perfectly round geometrical object in three-dimensional space that is the surface of a perfectly round ball. The key properties related to this problem are its surface area and volume.

  • The formula for the surface area of a sphere is \(A = 4 \pi r^2\), where \(A\) is the surface area and \(r\) is the radius of the sphere.
  • The formula for the volume of a sphere is \(V = \frac{4}{3} \pi r^3\), where \(V\) is the volume and \(r\) is the radius of the sphere.

Step-by-Step Solution

We are given that the surface area of the sphere is \(64 \pi \) cm2. We can use this information and the surface area formula to find the radius of the sphere.

Step 1: Find the Radius of the Sphere

We set the given surface area equal to the formula for the surface area:

\(4 \pi r^2 = 64 \pi \)

To find \(r^2\), we divide both sides by \(4 \pi \):

\(r^2 = \frac{64 \pi }{4 \pi }\)

\(r^2 = 16\)

Now, we take the square root of both sides to find the radius \(r\):

\(r = \sqrt{16}\)

\(r = 4\) cm

So, the radius of the sphere is 4 cm.

Step 2: Calculate the Volume of the Sphere

Now that we have the radius (\(r = 4\) cm), we can use the formula for the volume of a sphere:

\(V = \frac{4}{3} \pi r^3\)

Substitute the value of \(r\) into the formula:

\(V = \frac{4}{3} \pi (4)^3\)

Calculate \(4^3\):

\(4^3 = 4 \times 4 \times 4 = 16 \times 4 = 64\)

Substitute \(64\) back into the volume formula:

\(V = \frac{4}{3} \pi (64)\)

Multiply \(\frac{4}{3}\) by \(64\):

\(V = \frac{4 \times 64}{3} \pi \)

\(V = \frac{256}{3} \pi \)

The volume of the sphere is \(\frac{256}{3} \pi \) cm3.

Summary of Steps

StepActionCalculation
1Use surface area to find radius\(4 \pi r^2 = 64 \pi \implies r^2 = 16 \implies r = 4\) cm
2Use radius to find volume\(V = \frac{4}{3} \pi (4)^3 = \frac{4}{3} \pi (64) = \frac{256}{3} \pi \) cm3


 

Comparing our calculated volume with the given options, we find that it matches option 4.

Revision Table: Sphere Geometry Formulas

PropertyFormulaVariables
Surface Area\(A = 4 \pi r^2\)\(A\) = Surface Area, \(r\) = Radius
Volume\(V = \frac{4}{3} \pi r^3\)\(V\) = Volume, \(r\) = Radius
Circumference of Great Circle\(C = 2 \pi r\)\(C\) = Circumference, \(r\) = Radius


 

Additional Information: Understanding Spheres

A sphere is a fundamental 3D shape. It is defined as the set of all points in three-dimensional space that are equally distant from a given point, called the center. The constant distance is called the radius.

  • Unlike shapes like cubes or cylinders, a sphere has no edges or vertices.
  • Every cross-section through the center of a sphere is a circle called a 'great circle'. The equator on Earth is an example of a great circle (if Earth were a perfect sphere).
  • The formulas for surface area and volume of a sphere were first rigorously derived by the ancient Greek mathematician Archimedes. He showed that the surface area of a sphere is equal to the lateral surface area of a circumscribed cylinder, and the volume of a sphere is two-thirds the volume of a circumscribed cylinder.
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Important Questions from Solid Figures

  1. A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?

  2. A metallic solid cuboid of dimensions 36 cm × 18 cm × 12 cm is melted and recast in the form of cubes of side 6 cm. Find the number of cubes so formed.

  3. A solid cylinder has a radius of 9 cm and a height of 25 cm. What is the ratio of its total surface area to its curved surface area?

  4. Find the surface area of a sphere of diameter 21 cm. (Use π = \(\frac{{22}}{7}\) )

  5. A cuboid of dimension 24 cm, 9 cm and 8 cm is melted and smaller cubes of side 3 cm are formed. How many such cubes can be formed?

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