All Exams Test series for 1 year @ ₹349 only
Question

The radius of a right circular cylinder is four times of its height. If the height of the cylinder is 14 cm, then what is the volume of cylinder?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

137984 cm3

Calculating the Volume of a Right Circular Cylinder

The problem asks us to find the volume of a right circular cylinder given its height and a relationship between its radius and height.

We are given the following information about the right circular cylinder:

  • The height of the cylinder, \(h = 14 \, \text{cm}\).
  • The radius (\(r\)) of the cylinder is four times its height (\(h\)).

First, let's determine the radius of the cylinder using the given relationship:

Radius, \(r = 4 \times h\)

Substitute the given height, \(h = 14 \, \text{cm}\):

\(r = 4 \times 14 \, \text{cm}\)

\(r = 56 \, \text{cm}\)

Now that we have both the radius (\(r\)) and the height (\(h\)), we can calculate the volume of the right circular cylinder using the formula:

\(V = \pi r^2 h\)

We will use the value of \(\pi\) as \(22/7\) for this calculation, as it often yields integer results in such problems.

Substitute the values of \(r = 56 \, \text{cm}\) and \(h = 14 \, \text{cm}\) into the volume formula:

\(V = \frac{22}{7} \times (56 \, \text{cm})^2 \times 14 \, \text{cm}\)

\(V = \frac{22}{7} \times (56 \times 56) \, \text{cm}^2 \times 14 \, \text{cm}\)

\(V = \frac{22}{7} \times 3136 \, \text{cm}^2 \times 14 \, \text{cm}\)

We can simplify the calculation by dividing 14 by 7:

\(V = 22 \times 3136 \, \text{cm}^2 \times \frac{14}{7} \, \text{cm}\)

\(V = 22 \times 3136 \, \text{cm}^2 \times 2 \, \text{cm}\)

Now, multiply the numbers together:

\(V = 22 \times (3136 \times 2) \, \text{cm}^3\)

\(V = 22 \times 6272 \, \text{cm}^3\)

Let's perform the final multiplication:

\(22 \times 6272 = (20 + 2) \times 6272\)

\(= 20 \times 6272 + 2 \times 6272\)

\(= 125440 + 12544\)

\(= 137984\)

So, the volume of the cylinder is \(137984 \, \text{cm}^3\).

Let's summarise the key values:

Parameter Value
Height (\(h\)) 14 cm
Radius (\(r = 4h\)) 56 cm
\(\pi\) (assumed) \(22/7\)
Volume (\(V\)) \(137984 \, \text{cm}^3\)

Comparing this result with the given options, we find that the calculated volume matches one of the options.

Revision Table: Cylinder Volume Calculation Steps

Step Description Formula/Calculation
1 Identify given height. \(h = 14 \, \text{cm}\)
2 Calculate radius from height relationship. \(r = 4h = 4 \times 14 = 56 \, \text{cm}\)
3 Recall volume formula for cylinder. \(V = \pi r^2 h\)
4 Substitute values and calculate. \(V = \frac{22}{7} \times (56)^2 \times 14 = \frac{22}{7} \times 3136 \times 14 = 22 \times 3136 \times 2 = 137984 \, \text{cm}^3\)

Additional Information on Right Circular Cylinders

A right circular cylinder is a three-dimensional solid with two parallel circular bases of the same size, connected by a curved surface. The axis joining the centers of the bases is perpendicular to the bases. Key properties and formulas include:

  • Base: A circle.
  • Area of Base: \(A_{\text{base}} = \pi r^2\), where \(r\) is the radius of the base.
  • Lateral Surface Area: The area of the curved surface. \(A_{\text{lateral}} = 2\pi r h\), where \(h\) is the height. This is equal to the circumference of the base multiplied by the height.
  • Total Surface Area: The sum of the areas of the two bases and the lateral surface area. \(A_{\text{total}} = 2 \times A_{\text{base}} + A_{\text{lateral}} = 2\pi r^2 + 2\pi r h = 2\pi r (r + h)\).
  • Volume: The space occupied by the cylinder. \(V = (\text{Area of Base}) \times \text{height} = \pi r^2 h\).

Understanding these formulas is crucial for solving problems involving cylinders.

Was this answer helpful?

Similar Questions

  1. The curved surface area and the volume of a cylindrical object are 88 cm 2and 132 cm 3, respectively. The height (in cm) of the cylindrical object is:

    (Take π =   \(\frac{{22}}{7}\) )

  2. The circumference of the base of a cylindrical vessel is 264 cm and its height is 50 cm. The capacity (in litres) of the vessel is:

    (Take π =  \(\frac{22}{7}\) )

  3. What will be the total cost (in Rs.) of polishing the curved surface of a wooden cylinder at rate of Rs. 50 per m 2, if its diameter is 70 cm and height is 6 m? (Take π =  \(\frac{22}{7}\) )

  4. A cylindrical tube, open at both ends, is made of a metal sheet which is 0.5 cm thick. Its outer radius is 4 cm and length is 2 m. How much metal (in cm 3) has been used in making the tube?

  5. The volume of a right circular cone is 308 cm 3 and the radius of its base is 7 cm. What is the curved surface area (in cm 2) of the cone? (Take π =  \(\frac{22}{7} \) )

  6. The slant height and radius of a right circular cone are in the ratio 29 ∶ 20. If its volume is 4838.4 π cm 3, then its radius is: 

  7. Six cubes, each of edge 2 cm, are joined end to end. What is the total surface area of the resulting cuboid in cm 2?

  8. The volume of a cone is 73920 cm3. If the height of the cone is 160 cm, then find the diameter of its base.

  9. The volume of a cone with height equal to radius, and slant height 5 cm is :

  10. How many metres of 2-m-wide cloth will be required to make a conical tent with a diameter of the base as 14 m and slant height as 9 m? (ignore wastage)


Important Questions from Solid Figures

  1. A cone and a hemisphere have equal bases and volumes. What is the ratio of the height of the cone to the radius of the hemisphere?

  2. If the surface area of a sphere is 64 π cm 2, then the volume of the sphere is:

  3. Find the surface area of a sphere of diameter 21 cm. (Use π = \(\frac{{22}}{7}\) )

  4. A cube is 7 cm of an edge and another cube is 14 cm on an edge. The ratios of their surface areas are

  5. Using three distinct points which of the following shapes cannot be formed?

Need Expert Advice?
Upcoming Exams
SSC CGL
September 30, 2026
UPSSSC PET
October 23, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2503 Tests 6 Tests Free
5384 Attempts
4.2(868)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App