The curved surface area and the volume of a cylindrical object are 88 cm 2and 132 cm 3, respectively. The height (in cm) of the cylindrical object is: (Take π = \(\frac{{22}}{7}\) )
This problem asks us to find the height of a cylindrical object given its curved surface area and volume. We are provided with the curved surface area (CSA) as 88 cm2 and the volume (V) as 132 cm3. We are also given the value of π as \(\frac{{22}}{7}\). To solve this, we will use the standard formulas for the curved surface area and volume of a cylinder.
Let 'r' be the radius of the base of the cylinder and 'h' be its height. The formulas are:
Using the given information, we can write two equations:
Equation 1 (from CSA):
\(2\pi r h = 88\)
Equation 2 (from Volume):
\(\pi r^2 h = 132\)
We can solve these two equations simultaneously to find the values of 'r' and 'h'. A common method is to divide the equation with the higher power of 'r' by the other equation. Let's divide Equation 2 by Equation 1:
\(\frac{\pi r^2 h}{2\pi r h} = \frac{132}{88}\)
Simplify the left side by cancelling common terms (\(\pi\), 'r', 'h'):
\(\frac{r}{2} = \frac{132}{88}\)
Now, simplify the fraction on the right side. Both 132 and 88 are divisible by 44 (since \(132 = 3 \times 44\) and \(88 = 2 \times 44\)):
\(\frac{r}{2} = \frac{3 \times 44}{2 \times 44}\)
\(\frac{r}{2} = \frac{3}{2}\)
Multiply both sides by 2 to find the radius 'r':
\(r = \frac{3}{2} \times 2\)
\(r = 3 \text{ cm}\)
Now that we have the radius \(r = 3\) cm, we can substitute this value into either Equation 1 or Equation 2 to find the height 'h'. Let's use Equation 1:
\(2\pi r h = 88\)
Substitute the values of \(\pi = \frac{22}{7}\) and \(r = 3\):
\(2 \times \frac{22}{7} \times 3 \times h = 88\)
\(\frac{44}{7} \times 3 \times h = 88\)
\(\frac{132}{7} \times h = 88\)
To isolate 'h', multiply both sides by \(\frac{7}{132}\):
\(h = 88 \times \frac{7}{132}\)
Simplify the fraction \(\frac{88}{132}\). Again, both are divisible by 44:
\(h = \frac{88}{132} \times 7\)
\(h = \frac{2 \times 44}{3 \times 44} \times 7\)
\(h = \frac{2}{3} \times 7\)
\(h = \frac{14}{3} \text{ cm}\)
The calculated height is \(\frac{14}{3}\) cm. To match the format of the options, we can convert this improper fraction into a mixed fraction:
\(\frac{14}{3} = \frac{12 + 2}{3} = \frac{12}{3} + \frac{2}{3} = 4 + \frac{2}{3} = 4\frac{2}{3}\)
So, the height of the cylindrical object is \(4\frac{2}{3}\) cm.
Let's compare our calculated height with the given options:
Our calculated height \(4\frac{2}{3}\) cm matches Option 2.
| Given Information | Formula Used | Calculated Value |
|---|---|---|
| Curved Surface Area = 88 cm2 | CSA = \(2\pi r h\) | Radius \(r = 3\) cm |
| Volume = 132 cm3 | Volume = \(\pi r^2 h\) | Height \(h = \frac{14}{3}\) cm or \(4\frac{2}{3}\) cm |
| \(\pi = \frac{22}{7}\) |
Understanding the properties of a cylinder is key to solving problems like this. Here are some related concepts:
By using the formulas correctly and performing algebraic manipulation, we successfully found the height of the cylindrical object.
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