The problem requires calculating the value of the expression $7\frac{2}{3} \times 5\frac{3}{4} + 9\frac{1}{2} \times 6\frac{3}{4}$. This involves converting mixed fractions to improper fractions, performing multiplications, and then adding the results.
Multiply the pairs of improper fractions:
Add the products obtained in Step 2. First, find a common denominator for 12 and 8, which is 24.
Divide the numerator 2597 by the denominator 24 to express the result as a mixed fraction.
$2597 \div 24 = 108$ with a remainder of $5$. ($108 \times 24 = 2592$; $2597 - 2592 = 5$).
Therefore, the value is $108\frac{5}{24}$.
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: