The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is _________ g (nearest integer).(Given molar mass in $\text{g mol}^{-1} \, \text{H} : 1, \text{C} : 12, \text{N} : 14, \text{O} : 16$)

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The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82%, is _________ g (nearest integer).
(Given molar mass in $\text{g mol}^{-1} \, \text{H} : 1, \text{C} : 12, \text{N} : 14, \text{O} : 16$)

Aniline Benzoylation: Reaction Chemistry & Molar Masses

The benzoylation reaction involves the synthesis of benzanilide from aniline. The key reaction is:

$ C_6H_5NH_2 + C_6H_5COCl \rightarrow C_6H_5NHCOC_6H_5 + HCl $

Molar masses calculated using the given atomic masses (H: 1, C: 12, N: 14, O: 16) are:

Aniline ($C_6H_5NH_2$): $ (6 \times 12) + (5 \times 1) + 14 + (2 \times 1) = 93 \, \text{g/mol} $.
Benzanilide ($C_{13}H_{11}NO$): $ (13 \times 12) + (11 \times 1) + 14 + 16 = 197 \, \text{g/mol} $.

Aniline Moles Calculation

Calculate the moles of aniline used from its given mass:

$ \text{Moles of Aniline} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{5.8 \, \text{g}}{93 \, \text{g/mol}} $

Theoretical Benzanilide Calculation

Based on the reaction stoichiometry (1:1 mole ratio), the theoretical moles of benzanilide equal the moles of aniline. The theoretical mass is:

$ \text{Theoretical Mass} = \left( \frac{5.8}{93} \right) \, \text{mol} \times 197 \, \text{g/mol} $

$ \text{Theoretical Mass} \approx 12.29 \, \text{g} $

Actual Benzanilide Mass Calculation

The actual mass obtained considers the reaction yield (82%):

$ \text{Actual Mass} = \text{Theoretical Mass} \times \frac{\text{Yield}}{100\%} $

$ \text{Actual Mass} = 12.29 \, \text{g} \times \frac{82}{100} $

$ \text{Actual Mass} \approx 10.07 \, \text{g} $

Final Benzanilide Mass Rounding

Rounding the calculated actual mass to the nearest integer gives the final answer:

$ 10.07 \, \text{g} \approx 10 \, \text{g} $

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Important Questions from Organic Chemistry

In Dumas method for estimation of nitrogen, 0.50 g of an organic compound gave 70 mL of nitrogen collected at 300 K and 715 mm pressure. The percentage of nitrogen in the organic compound is ______ %.
(Aqueous tension at 300 K is 15 mm).
JEE Main
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Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below
JEE Main
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Given below are two statements:
Statement I: Cross aldol condensation between two different aldehydes will always produce four different products.
Statement II: When semicarbazide reacts with a mixture of benzaldehyde and acetophenone under optimum pH, it forms a condensation product with acetophenone only.
In the light of the above statements, choose the correct answer from the options given below
JEE Main
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$0.25 \text{ g}$ of an organic compound "A" containing carbon, hydrogen and oxygen was analysed using the combustion method. There was an increase in mass of $\text{CaCl}_2$ tube and potash tube at the end of the experiment. The amount was found to be $0.15 \text{ g}$ and $0.1837 \text{ g}$, respectively. The percentage of oxygen in compound A is ______ %. (Nearest integer)
(Given: molar mass in $\text{g mol}^{-1}$ $\text{H} : 1, \text{C} : 12, \text{O} : 16$)
JEE Main
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Grignard reagent $\text{RMgBr (P)}$ reacts with water and forms a gas $\text{(Q)}$. One gram of Q occupies $1.4 \text{ dm}^3$ at STP. (P) on reaction with dry ice in dry ether followed by $\text{H}_3\text{O}^+$ forms a compound $\text{(Z)}$. 0.1 mole of $\text{(Z)}$ will weigh _________ g. (Nearest integer)
JEE Main
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