Statement I: Cross aldol condensation between two different aldehydes will always produce four different products.
Statement II: When semicarbazide reacts with a mixture of benzaldehyde and acetophenone under optimum pH, it forms a condensation product with acetophenone only.
In the light of the above statements, choose the correct answer from the options given below
Statement I asserts that cross aldol condensation between two distinct aldehydes always yields four different products.
This statement is false. The number of possible products is contingent upon the presence of alpha-hydrogens in the reacting aldehydes.
Because the number of products is variable and not consistently four, Statement I is false.
Statement II proposes that semicarbazide reacts exclusively with acetophenone, forming a product only with it, when mixed with benzaldehyde under optimal pH.
This statement is also false.
Consequently, semicarbazide would be expected to react with both benzaldehyde and acetophenone, not solely with acetophenone. Therefore, Statement II is false.
Based on the analysis, both Statement I and Statement II are demonstrably false.
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below
Given below are two statements :
Statement I : Compound (X), shown below, dissolves in $\text{NaHCO}_3$ solution and has two chiral carbon atoms 
Statement II : Compound (Y), shown below, has two carbons with $\text{sp}^3$ hybridization, one carbon with $\text{sp}^2$ and one carbon with $\text{sp}$ hybridization 
In the light of the above statements, choose the correct answer from the options given below :

Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below