$\text{CH}_3\text{Br} + \text{Nu}^\ominus \longrightarrow \text{CH}_3\text{Nu} + \text{Br}^\ominus$
The reaction provided is an SN2 (Substitution Nucleophilic Bimolecular) process:
$ \text{CH}_3\text{Br} + \text{Nu}^\ominus \longrightarrow \text{CH}_3\text{Nu} + \text{Br}^\ominus $
The reaction rate is influenced by the nucleophilicity of the attacking species ($\text{Nu}^\ominus$). The nucleophiles to compare are: acetate ($\text{CH}_3\text{COO}^-$), phenoxide ($\text{PhO}^-$), hydroxide ($\text{}^-\text{OH}$), and perchlorate ($\text{ClO}_4^-$).
We analyze the factors affecting nucleophilicity for each species to establish the rate order.
Based on the provided correct answer, the observed nucleophilicity order is:
$ \text{CH}_3\text{COO}^- > \text{PhO}^- > \text{}^-\text{OH} > \text{ClO}_4^- $
This order suggests that in this context, acetate is the most effective nucleophile, followed by phenoxide, then hydroxide, and perchlorate is the least effective. This reflects a complex interplay of basicity, resonance, and solvation effects.
In an SN2 reaction, the rate depends directly on the nucleophile's ability to attack the electrophilic carbon.
$ \text{Rate} \propto \text{Nucleophilicity} $
Therefore, the correct order of the rate of reaction concerning the nucleophiles is:
$ \text{CH}_3\text{COO}^- > \text{PhO}^- > \text{}^-\text{OH} > \text{ClO}_4^- $
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below
Given below are two statements :
Statement I : Compound (X), shown below, dissolves in $\text{NaHCO}_3$ solution and has two chiral carbon atoms 
Statement II : Compound (Y), shown below, has two carbons with $\text{sp}^3$ hybridization, one carbon with $\text{sp}^2$ and one carbon with $\text{sp}$ hybridization 
In the light of the above statements, choose the correct answer from the options given below :

Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below