A. Activation energy for enzyme catalysed hydrolysis of sucrose is lower than that of acid catalysed hydrolysis.
B. During denaturation, secondary and tertiary structures of a protein are destroyed but primary structure remains intact.
C. Nucleotides are joined together by glycosidic linkage between $\text{C}_1$ and $\text{C}_4$ carbons of the pentose sugar.
D. Quaternary structure of proteins represents overall folding of the polypeptide chain.
Choose the correct answer from the options given below :
Enzymes act as biological catalysts. They significantly lower the activation energy required for a biochemical reaction compared to non-biological catalysts like acids. For the hydrolysis of sucrose, enzyme-catalyzed hydrolysis requires less activation energy than acid-catalyzed hydrolysis.
Conclusion: Statement A is correct.
Protein denaturation involves the disruption of the higher-order structures: the secondary structure (e.g., alpha-helices, beta-sheets) and the tertiary structure (the overall 3D folding of a single polypeptide chain). These structures are maintained by relatively weak bonds (hydrogen bonds, hydrophobic interactions, ionic bonds) and disulfide bridges. The primary structure, which is the sequence of amino acids linked by strong covalent peptide bonds, remains intact during denaturation.
Conclusion: Statement B is correct.
Nucleotides are the monomers of nucleic acids (DNA and RNA). They are linked together by phosphodiester bonds. These bonds form between the phosphate group attached to the 5' carbon of one pentose sugar and the hydroxyl group on the 3' carbon of the pentose sugar of the next nucleotide.
Glycosidic linkages are typically found connecting monosaccharides in polysaccharides or linking the nitrogenous base to the pentose sugar in a nucleotide.
Conclusion: Statement C is incorrect.
The quaternary structure of proteins refers to the arrangement and interaction of multiple polypeptide chains (subunits) that associate to form a functional protein complex. While the folding of a single polypeptide chain constitutes the tertiary structure, the quaternary structure describes how these already folded chains are assembled and oriented relative to each other.
Conclusion: Statement D is correct.
Based on the analysis:
Therefore, the correct statements are A, B, and D.
The option including A, B, and D is Option 1.
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below
Given below are two statements :
Statement I : Compound (X), shown below, dissolves in $\text{NaHCO}_3$ solution and has two chiral carbon atoms 
Statement II : Compound (Y), shown below, has two carbons with $\text{sp}^3$ hybridization, one carbon with $\text{sp}^2$ and one carbon with $\text{sp}$ hybridization 
In the light of the above statements, choose the correct answer from the options given below :

Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below