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Question

Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below

The correct answer is
Statement I is false but Statement II is true

Let's analyze the statements one by one to identify which statement is correct.

Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce \(R-\text{COOH}\).

Analysis:

  • The dipole moment of the nitrile group \(R-\text{CN}\) is generally greater than that of the isonitrile group \(R-\text{NC}\) because the nitrogen atom in nitriles (R-CN) contributes more significantly to the dipole due to better resonance and linear structure.
  • However, R-NC (isonitrile) typically does not hydrolyze to produce carboxylic acid. Therefore, this part of the statement is inaccurate.

Conclusion for Statement I: False, because R-NC does not produce carboxylic acid upon hydrolysis under acidic conditions.

Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with \(\text{SOCl}_2\), followed by the addition of \(\text{NH}_3\) gives another compound (x). This compound (x) on treatment with \(\text{NaOCl/NaOH}\) gives a product, that on treatment with \(\text{CHCl}_3/\text{KOH}/\Delta\) produces R-NC.

Analysis:

  • R-CN hydrolyzes to form the corresponding carboxylic acid \(R-\text{COOH}\).
  • Treatment with \(\text{SOCl}_2\) converts the carboxylic acid to an acid chloride \(R-\text{COCl}\).
  • Addition of \(\text{NH}_3\) converts the acid chloride to an amide \(R-\text{CONH}_2\).
  • Treatment of the amide with \(\text{NaOCl/NaOH}\) results in the Hofmann rearrangement, forming an isocyanate that quickly rearranges to amine.
  • The formation of R-NC involves a reaction between the amine and chloroform in an alkaline medium.

Conclusion for Statement II: True, as the procedure described is a viable synthetic pathway from nitrile to isonitrile.

Final Answer: Statement I is false but Statement II is true.

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Important Questions from Organic Chemistry

  1. In Dumas method for estimation of nitrogen, 0.50 g of an organic compound gave 70 mL of nitrogen collected at 300 K and 715 mm pressure. The percentage of nitrogen in the organic compound is ______ %.
    (Aqueous tension at 300 K is 15 mm).
  2. Given below are two statements:
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    Statement II: When semicarbazide reacts with a mixture of benzaldehyde and acetophenone under optimum pH, it forms a condensation product with acetophenone only.
    In the light of the above statements, choose the correct answer from the options given below
  3. $0.25 \text{ g}$ of an organic compound "A" containing carbon, hydrogen and oxygen was analysed using the combustion method. There was an increase in mass of $\text{CaCl}_2$ tube and potash tube at the end of the experiment. The amount was found to be $0.15 \text{ g}$ and $0.1837 \text{ g}$, respectively. The percentage of oxygen in compound A is ______ %. (Nearest integer)
    (Given: molar mass in $\text{g mol}^{-1}$ $\text{H} : 1, \text{C} : 12, \text{O} : 16$)
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    (b) iso-propyl chloride
    (c) sec-butyl chloride
    (d) neo-pentyl chloride
    Percentage of carbon in the one which exhibits optical isomerism is :
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