(a) n-propyl choride
(b) iso-propyl chloride
(c) sec-butyl chloride
(d) neo-pentyl chloride
Percentage of carbon in the one which exhibits optical isomerism is :
Optical isomerism occurs in compounds that possess a chiral center. A chiral center is typically a carbon atom bonded to four different functional groups.
Therefore, sec-butyl chloride is the compound that exhibits optical isomerism.
The molecular formula for sec-butyl chloride is C$_4$H$_9$Cl.
To find the percentage of carbon by mass, we use the atomic masses:
Calculate the molar mass of C$_4$H$_9$Cl:
Molar Mass $= (4 \times 12.011) + (9 \times 1.008) + (1 \times 35.453)$
Molar Mass $= 48.044 + 9.072 + 35.453 = 92.569$ amu
Calculate the percentage of carbon:
Percentage of Carbon $= \frac{\text{Mass of Carbon}}{\text{Molar Mass}} \times 100$
Percentage of Carbon $= \frac{4 \times 12.011}{92.569} \times 100$
Percentage of Carbon $= \frac{48.044}{92.569} \times 100 \approx 51.899\%$
sec-butyl chloride is the optically active compound. The calculated percentage of carbon is approximately $51.9\%$. Among the given options, $56$ is listed as the correct answer (Option A).
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below
Given below are two statements :
Statement I : Compound (X), shown below, dissolves in $\text{NaHCO}_3$ solution and has two chiral carbon atoms 
Statement II : Compound (Y), shown below, has two carbons with $\text{sp}^3$ hybridization, one carbon with $\text{sp}^2$ and one carbon with $\text{sp}$ hybridization 
In the light of the above statements, choose the correct answer from the options given below :

Consider the above sequence of reactions. The number of bromine atom(s) in the final product (P) will be :
Given below are two statements:
Statement I: The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce 
Statement II: R-CN hydrolyses under acidic medium to produce a compound which on treatment with $\text{SOCl}_2$, followed by the addition of $\text{NH}_3$ gives another compound(x). This compound (x) on treatment with $\text{NaOCl/NaOH}$ gives a product, that on treatment with $\text{CHCl}_3\text{/KOH/}\Delta$ produces R-NC
In the light of the above statements, choose the correct answer from the options given below