This problem requires calculating the total distance of Suhas's journey based on fractions covered by different modes of transport and the remaining distance covered by bicycle.
Fraction by train = $\frac{5}{12}$
Fraction by bus = $\frac{1}{3}$
Total fraction (train + bus) = $\frac{5}{12} + \frac{1}{3}$
To add these fractions, find a common denominator, which is 12:
Total fraction = $\frac{5}{12} + \frac{1 \times 4}{3 \times 4} = \frac{5}{12} + \frac{4}{12} = \frac{9}{12}$
Simplify the fraction: $\frac{9}{12} = \frac{3}{4}$
The total journey represents 1 whole.
Fraction by bicycle = Total journey - Fraction (train + bus)
Fraction by bicycle = $1 - \frac{3}{4} = \frac{4}{4} - \frac{3}{4} = \frac{1}{4}$
We are given that the remaining distance covered by bicycle is 36 km.
This means $\frac{1}{4}$ of the total journey is equal to 36 km.
Let the total distance be $D$. Then:
$\frac{1}{4} \times D = 36 \text{ km}$
To find the total distance $D$, multiply the distance by bicycle by 4:
$D = 36 \text{ km} \times 4$
$D = 144 \text{ km}$
Therefore, Suhas traveled a total of 144 km.
What is the value of
$\frac{7}{9} - \frac{11}{12} + \frac{13}{16} - \frac{1}{8}$?
5 \(\frac{3}{4}\) + x + 2 \(\frac{1}{2}\) = 10 \(\frac{1}{8}\) Find the value of x.
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
Number 0.232323 can be written in rational form as:
Solve: \(\frac{1}{2}\) [{-2(2 + 3)*20}/2]
Match the following.
Column I | Column II | ||
a. | Equivalent fraction of \(\frac{7}{12}\) is | i. | Proper fraction |
b. | Equivalent fraction of \(\frac{9}{15}\) is | ii. | Improper fraction |
c. | \(\frac{7}{11}\) is | iii. | \(\frac{21}{36}\) |
d. | \(\frac{19}{5}\) is | iv. | \(\frac{3}{5}\) |