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Simplify: \(\left\{\dfrac{12}{27} \div \dfrac{12}{2}\right\} \div \left(\dfrac{1}{11} \times \dfrac{22}{3} + \dfrac{5}{9}\right) + \dfrac{2}{9} \div \dfrac{33}{22} \text{ of } \dfrac{22}{9}\)

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RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is

\(\dfrac{4}{33}\)

\(\dfrac{12}{27}\div\dfrac{12}{2} = \dfrac{12}{27}\times\dfrac{2}{12} = \dfrac{2}{27}\).

Inside the bracket: \(\dfrac{1}{11}\times\dfrac{22}{3} = \dfrac{2}{3}\), plus \(\dfrac59\) gives \(\dfrac23+\dfrac59 = \dfrac{6+5}{9} = \dfrac{11}{9}\).

First part: \(\dfrac{2}{27}\div\dfrac{11}{9} = \dfrac{2}{27}\times\dfrac{9}{11} = \dfrac{2}{33}\).

For the 'of' term: \(\dfrac{33}{22}\text{ of }\dfrac{22}{9} = \dfrac{33}{22}\times\dfrac{22}{9} = \dfrac{33}{9} = \dfrac{11}{3}\).

Second part: \(\dfrac29\div\dfrac{11}{3} = \dfrac29\times\dfrac{3}{11} = \dfrac{2}{33}\).

Adding both parts: \(\dfrac{2}{33}+\dfrac{2}{33} = \dfrac{4}{33}\).

Hence, the simplified value of the expression is \(\tfrac{4}{33}\).

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