Pipe A can fill a tank in X hours. Pipe B can empty it in 15 hours. If both the pipes are opened together, then the tank will be filled in 7 hours and 30 minutes. Find X.
5
Given,
Pipe A can fill a tank in X hours
Pipe B can empty a full tank in 15 hours
If both Pipe A and Pipe B are open, the tank gets filled in 7 hours 30 minutes = (7 + 1/2) = 15/2 hours
Formula:
Total work = Efficiency × Time taken
Calculation:
Total work = 15 units
⇒ Efficiency of B = (-1) unit/hour
Let the efficiency of A be t, then
t – 1 = 2
⇒ t = 2 + 1
⇒ t = 3 units/hour
∴ Pipe A alone can fill the tank = 15/3 = 5 hours
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