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Question

  Match the following :

List – I List – II
a. Power efficient transmissioni. SSB-SC
b. Most bandwidth efficient transmission of voice signalii. VSB
c. Simplest receiveriii. FM
d. Bandwidth efficient transmission of signals with significant d.c. componentiv. AM

Codes :

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

a-iii, b-i, c-iv, d-ii

 Each scheme is matched to the single respect in which it is best: a-iii, b-i, c-iv, d-ii — option 2.

RequirementSchemeWhy
a. Power efficientiii. FMConstant envelope; noise traded for bandwidth
b. Bandwidth efficient (voice)i. SSB-SCHalf the bandwidth, no carrier
c. Simplest receiveriv. AMA diode envelope detector suffices
d. Signals with DC contentii. VSBRetains a vestige near DC

a — FM's power efficiency. Its envelope is constant, so the transmitter's output stage can be run in class C or saturated switching — 70 % efficient or better — whereas a linear AM stage must stay linear and wastes power doing so. FM also converts extra bandwidth into signal-to-noise improvement, so a given quality is achieved with less transmitted power.

b — SSB for voice. The two sidebands of an AM signal carry identical information, so one is pure redundancy. Removing it halves the occupied bandwidth to \(f_{m}\) and removing the carrier saves the two-thirds of power AM spends on it. Speech tolerates this well because it has no significant energy near DC — the audio band starts around 300 Hz — leaving room for the filter to cut cleanly between the sidebands. This is why long-distance HF voice communication is almost entirely SSB.

d — why VSB exists, and why it is not simply SSB. This is the pairing that explains the whole question. When a signal does have energy down to DC — television video is the standard case — SSB becomes impossible: the two sidebands meet at the carrier with no gap, and no filter can separate them without destroying the low-frequency content that carries the picture's average brightness. VSB is the compromise: transmit one sideband fully, plus a small vestige of the other, so the filter's gradual roll-off is symmetrical about the carrier and the low frequencies are recovered correctly. It costs a little more bandwidth than SSB but far less than DSB.

c — AM's one advantage. A diode, a capacitor and a resistor recover the envelope. That receiver simplicity is the entire justification for transmitting a carrier that carries no information, and it is why AM broadcasting outlived its inefficiency: transmitter power is spent once, while receivers are bought by millions.

Hence, the correct code is a-iii, b-i, c-iv, d-ii.

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Similar Questions

  1. Match the following lists :

    List – IList – II  
    a. PCMi. Slope overload distortion
    b. DMii. Constant carrier frequency
    c. AMiii. Encoding
    d. TDMiv. Commutator

    The correct match is :

  2. Match the following :

    List – I  List – II
    a. DSB-SC modulationi. envelope detection
    b. SSB-modulationii. Foster Seeley
    c. AM-demodulationiii. Weaver's method
    d. Phase-shift detectioniv. Balanced modulator

    Codes :

  3. Match List - I with List - II.

    List - IList - II  
    (A) White noise(I) Reduces antenna height
    (B) RMS noise voltage(II) \(P_{C}\left(\dfrac{m^{2}}{2}\right)\)
    (C) Modulation(III) Inversely proportional to \(\sqrt{T}\)
    (D) PDSBSC(IV) Johnson Noise

    Choose the correct answer from the options given below :

  4. Match the following lists :

    List - IList - II
    a) i) Frequency modulated detector
    b) ii) Pre-emphasis
    c)  iii)  Amplitude modulator
    d) iv) Amplitude detector

    Choose the correct answer from the codes given below:

  5. Match the following lists :

    List -I List - II
    a. Power efficient transmission of signalsi. AM
    b. Bandwidth efficient transmission of signals with significant dc signalsii. VSB
    c. Most bandwidth efficient transmission of voice signalsiii. SSB-SC
    d. Simplest Receiver Circuitiv. FM

     

    Correct Codes are :

  6. Arrange in order of the increasing Bandwidth value for the below mentioned systems :

    (a) DSB-SC      (b) VSB      (c) FM       (d) SSB

    Codes :


Important Questions from Modulation

  1. Which of the following modulations is used in India for radio transmission?

  2. Which of the following is a result of over-modulation?
  3. Which of the following statements are correct?

    A. DSB‐SC modulation is well suited for point to point communication involving one transmitter and one receiver.

    B. VSB modulation is a linear modulation scheme.

    C. SSB is a non‐linear modulation scheme.

    D. FM is a linear modulation scheme.

    Choose the correct answer from the options given below:

  4. The condition for achieving distortion-less demodulation of an amplitude-modulated signal using an envelope detector is

  5. When a broadcast AM transmitter is 50 % modulated, its antenna current is 12 A. What will be the current when the modulation depth is increased to 90%?

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