Match the following lists : Choose the correct answer from the codes given below:List - I List - II a) 
i) Frequency modulated detector b) 
ii) Pre-emphasis c) 
iii) Amplitude modulator d) 
iv) Amplitude detector
a-iv, b-i, c-iii, d-ii
Each circuit is identified by the one element that gives its function away.
a → iv. Amplitude detector. A series diode followed by a parallel R–C is the classic envelope detector. The diode rectifies the modulated carrier and the capacitor holds the peak between cycles, so the output follows the envelope — i.e. the message. The time constant must satisfy
\(\dfrac{1}{f_c}\ll RC\ll\dfrac{1}{f_m}\)
fast enough to follow the modulation but slow enough to smooth the carrier; too large an RC produces diagonal clipping.
b → i. Frequency modulated detector. The giveaway is the tuned transformer feeding the diode. An FM detector must first convert frequency variations into amplitude variations, and a tuned circuit operated on the slope of its response does exactly that; the diode and RC then recover the resulting envelope. This slope/ratio-detector arrangement is the standard FM demodulator.
c → iii. Amplitude modulator. Here the diode is driven from a resistive divider and its output feeds an L–C tuned tank. The non-linear diode mixes the carrier and modulating signals, generating sum and difference frequencies, and the tank selects the wanted band around the carrier — producing AM rather than detecting it. Non-linearity plus a tuned output is always a modulator.
d → ii. Pre-emphasis. The audio enters a transistor whose collector load is an inductor in series with a resistor. Since \(X_L=\omega L\) rises with frequency, so does the stage gain: the circuit deliberately boosts the treble before modulation. At the receiver a matching de-emphasis network restores the balance and, in doing so, attenuates the high-frequency noise that FM detection produces — improving the output signal-to-noise ratio. The standard time constant is 75 μs.
Recognition rule: diode + RC → detector; tuned transformer ahead of the diode → FM detector; non-linear device with a tuned output → modulator; a series L in the load → a deliberate high-frequency boost, i.e. pre-emphasis.
Hence, the correct matching is a-iv, b-i, c-iii, d-ii.
Match the following lists :
| List – I | List – II |
| a. PCM | i. Slope overload distortion |
| b. DM | ii. Constant carrier frequency |
| c. AM | iii. Encoding |
| d. TDM | iv. Commutator |
The correct match is :
Match the following :
| List – I | List – II |
| a. DSB-SC modulation | i. envelope detection |
| b. SSB-modulation | ii. Foster Seeley |
| c. AM-demodulation | iii. Weaver's method |
| d. Phase-shift detection | iv. Balanced modulator |
Codes :
Match the following :
| List – I | List – II |
| a. Power efficient transmission | i. SSB-SC |
| b. Most bandwidth efficient transmission of voice signal | ii. VSB |
| c. Simplest receiver | iii. FM |
| d. Bandwidth efficient transmission of signals with significant d.c. component | iv. AM |
Codes :
Match the following lists :
| List -I | List - II |
| a. Power efficient transmission of signals | i. AM |
| b. Bandwidth efficient transmission of signals with significant dc signals | ii. VSB |
| c. Most bandwidth efficient transmission of voice signals | iii. SSB-SC |
| d. Simplest Receiver Circuit | iv. FM |
Correct Codes are :
Arrange in order of the increasing Bandwidth value for the below mentioned systems :
(a) DSB-SC (b) VSB (c) FM (d) SSB
Codes :
Match List - I with List - II.
| List - I | List - II |
| (A) White noise | (I) Reduces antenna height |
| (B) RMS noise voltage | (II) \(P_{C}\left(\dfrac{m^{2}}{2}\right)\) |
| (C) Modulation | (III) Inversely proportional to \(\sqrt{T}\) |
| (D) PDSBSC | (IV) Johnson Noise |
Choose the correct answer from the options given below :
What is the duty cycle of a radar with pulse width 0.3 µs and pulse repetation rate of 1 ms ?
In an AM with m=1, the power in one sideband is:
Match the following lists :
| List – I | List – II |
| a. PCM | i. Slope overload distortion |
| b. DM | ii. Constant carrier frequency |
| c. AM | iii. Encoding |
| d. TDM | iv. Commutator |
The correct match is :
Match the following :
| List – I | List – II |
| a. DSB-SC modulation | i. envelope detection |
| b. SSB-modulation | ii. Foster Seeley |
| c. AM-demodulation | iii. Weaver's method |
| d. Phase-shift detection | iv. Balanced modulator |
Codes :