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Question

Match the following lists :

List - IList - II
a) i) Frequency modulated detector
b) ii) Pre-emphasis
c)  iii)  Amplitude modulator
d) iv) Amplitude detector

Choose the correct answer from the codes given below:

This question was previously asked in
UGC NET 2016 Paper 3 Electronic Science Question Paper (10-Jul-2016)
The correct answer is

a-iv, b-i, c-iii, d-ii

Each circuit is identified by the one element that gives its function away.

a → iv. Amplitude detector. A series diode followed by a parallel R–C is the classic envelope detector. The diode rectifies the modulated carrier and the capacitor holds the peak between cycles, so the output follows the envelope — i.e. the message. The time constant must satisfy

\(\dfrac{1}{f_c}\ll RC\ll\dfrac{1}{f_m}\)

fast enough to follow the modulation but slow enough to smooth the carrier; too large an RC produces diagonal clipping.

b → i. Frequency modulated detector. The giveaway is the tuned transformer feeding the diode. An FM detector must first convert frequency variations into amplitude variations, and a tuned circuit operated on the slope of its response does exactly that; the diode and RC then recover the resulting envelope. This slope/ratio-detector arrangement is the standard FM demodulator.

c → iii. Amplitude modulator. Here the diode is driven from a resistive divider and its output feeds an L–C tuned tank. The non-linear diode mixes the carrier and modulating signals, generating sum and difference frequencies, and the tank selects the wanted band around the carrier — producing AM rather than detecting it. Non-linearity plus a tuned output is always a modulator.

d → ii. Pre-emphasis. The audio enters a transistor whose collector load is an inductor in series with a resistor. Since \(X_L=\omega L\) rises with frequency, so does the stage gain: the circuit deliberately boosts the treble before modulation. At the receiver a matching de-emphasis network restores the balance and, in doing so, attenuates the high-frequency noise that FM detection produces — improving the output signal-to-noise ratio. The standard time constant is 75 μs.

Recognition rule: diode + RC → detector; tuned transformer ahead of the diode → FM detector; non-linear device with a tuned output → modulator; a series L in the load → a deliberate high-frequency boost, i.e. pre-emphasis.

Hence, the correct matching is a-iv, b-i, c-iii, d-ii.

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Similar Questions

  1. Match the following lists :

    List – IList – II  
    a. PCMi. Slope overload distortion
    b. DMii. Constant carrier frequency
    c. AMiii. Encoding
    d. TDMiv. Commutator

    The correct match is :

  2. Match the following :

    List – I  List – II
    a. DSB-SC modulationi. envelope detection
    b. SSB-modulationii. Foster Seeley
    c. AM-demodulationiii. Weaver's method
    d. Phase-shift detectioniv. Balanced modulator

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  3.   Match the following :

    List – I List – II
    a. Power efficient transmissioni. SSB-SC
    b. Most bandwidth efficient transmission of voice signalii. VSB
    c. Simplest receiveriii. FM
    d. Bandwidth efficient transmission of signals with significant d.c. componentiv. AM

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  4. Match List - I with List - II.

    List - IList - II  
    (A) White noise(I) Reduces antenna height
    (B) RMS noise voltage(II) \(P_{C}\left(\dfrac{m^{2}}{2}\right)\)
    (C) Modulation(III) Inversely proportional to \(\sqrt{T}\)
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    Choose the correct answer from the options given below :

  5. Match the following lists :

    List -I List - II
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    Correct Codes are :

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Important Questions from Modulation

  1. Combining the low frequency signal with very high frequency radio wave is called
  2. During the heterodyne process in the receiver, the modulation of the signal __________

  3. Which of the following modulations is used in India for radio transmission?

  4. Which of the following is a result of over-modulation?
  5. Which of the following statements are correct?

    A. DSB‐SC modulation is well suited for point to point communication involving one transmitter and one receiver.

    B. VSB modulation is a linear modulation scheme.

    C. SSB is a non‐linear modulation scheme.

    D. FM is a linear modulation scheme.

    Choose the correct answer from the options given below:

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