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Question

Match the following lists :

List - IList - II
a) i) Frequency modulated detector
b) ii) Pre-emphasis
c)  iii)  Amplitude modulator
d) iv) Amplitude detector

Choose the correct answer from the codes given below:

This question was previously asked in
UGC NET 2016 Paper 1 Question Paper (10-Jul-2016)
The correct answer is

a-iv, b-i, c-iii, d-ii

Each circuit is identified by the one element that gives its function away.

a → iv. Amplitude detector. A series diode followed by a parallel R–C is the classic envelope detector. The diode rectifies the modulated carrier and the capacitor holds the peak between cycles, so the output follows the envelope — i.e. the message. The time constant must satisfy

\(\dfrac{1}{f_c}\ll RC\ll\dfrac{1}{f_m}\)

fast enough to follow the modulation but slow enough to smooth the carrier; too large an RC produces diagonal clipping.

b → i. Frequency modulated detector. The giveaway is the tuned transformer feeding the diode. An FM detector must first convert frequency variations into amplitude variations, and a tuned circuit operated on the slope of its response does exactly that; the diode and RC then recover the resulting envelope. This slope/ratio-detector arrangement is the standard FM demodulator.

c → iii. Amplitude modulator. Here the diode is driven from a resistive divider and its output feeds an L–C tuned tank. The non-linear diode mixes the carrier and modulating signals, generating sum and difference frequencies, and the tank selects the wanted band around the carrier — producing AM rather than detecting it. Non-linearity plus a tuned output is always a modulator.

d → ii. Pre-emphasis. The audio enters a transistor whose collector load is an inductor in series with a resistor. Since \(X_L=\omega L\) rises with frequency, so does the stage gain: the circuit deliberately boosts the treble before modulation. At the receiver a matching de-emphasis network restores the balance and, in doing so, attenuates the high-frequency noise that FM detection produces — improving the output signal-to-noise ratio. The standard time constant is 75 μs.

Recognition rule: diode + RC → detector; tuned transformer ahead of the diode → FM detector; non-linear device with a tuned output → modulator; a series L in the load → a deliberate high-frequency boost, i.e. pre-emphasis.

Hence, the correct matching is a-iv, b-i, c-iii, d-ii.

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Similar Questions

  1. Match the following lists :

    List – IList – II  
    a. PCMi. Slope overload distortion
    b. DMii. Constant carrier frequency
    c. AMiii. Encoding
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    The correct match is :

  2. Match the following :

    List – I  List – II
    a. DSB-SC modulationi. envelope detection
    b. SSB-modulationii. Foster Seeley
    c. AM-demodulationiii. Weaver's method
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  3.   Match the following :

    List – I List – II
    a. Power efficient transmissioni. SSB-SC
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  4. Match the following lists :

    List -I List - II
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    b. Bandwidth efficient transmission of signals with significant dc signalsii. VSB
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  6. Match List - I with List - II.

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    Choose the correct answer from the options given below :


Important Questions from Modulation

  1. What is the duty cycle of a radar with pulse width 0.3 µs and pulse repetation rate of 1 ms ?

  2. An advantage of modulation is the use of _____.
  3. In an AM with m=1, the power in one sideband is:

  4. Match the following lists :

    List – IList – II  
    a. PCMi. Slope overload distortion
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    c. AMiii. Encoding
    d. TDMiv. Commutator

    The correct match is :

  5. Match the following :

    List – I  List – II
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