All Exams Test series for 1 year @ ₹349 only
Question

Match the following lists :

List - IList - II
a) i) Frequency modulated detector
b) ii) Pre-emphasis
c)  iii)  Amplitude modulator
d) iv) Amplitude detector

Choose the correct answer from the codes given below:

This question was previously asked in
UGC NET 2016 Paper 3 Electronic Science Question Paper (10-Jul-2016)
The correct answer is

a-iv, b-i, c-iii, d-ii

Each circuit is identified by the one element that gives its function away.

a → iv. Amplitude detector. A series diode followed by a parallel R–C is the classic envelope detector. The diode rectifies the modulated carrier and the capacitor holds the peak between cycles, so the output follows the envelope — i.e. the message. The time constant must satisfy

\(\dfrac{1}{f_c}\ll RC\ll\dfrac{1}{f_m}\)

fast enough to follow the modulation but slow enough to smooth the carrier; too large an RC produces diagonal clipping.

b → i. Frequency modulated detector. The giveaway is the tuned transformer feeding the diode. An FM detector must first convert frequency variations into amplitude variations, and a tuned circuit operated on the slope of its response does exactly that; the diode and RC then recover the resulting envelope. This slope/ratio-detector arrangement is the standard FM demodulator.

c → iii. Amplitude modulator. Here the diode is driven from a resistive divider and its output feeds an L–C tuned tank. The non-linear diode mixes the carrier and modulating signals, generating sum and difference frequencies, and the tank selects the wanted band around the carrier — producing AM rather than detecting it. Non-linearity plus a tuned output is always a modulator.

d → ii. Pre-emphasis. The audio enters a transistor whose collector load is an inductor in series with a resistor. Since \(X_L=\omega L\) rises with frequency, so does the stage gain: the circuit deliberately boosts the treble before modulation. At the receiver a matching de-emphasis network restores the balance and, in doing so, attenuates the high-frequency noise that FM detection produces — improving the output signal-to-noise ratio. The standard time constant is 75 μs.

Recognition rule: diode + RC → detector; tuned transformer ahead of the diode → FM detector; non-linear device with a tuned output → modulator; a series L in the load → a deliberate high-frequency boost, i.e. pre-emphasis.

Hence, the correct matching is a-iv, b-i, c-iii, d-ii.

Was this answer helpful?

Similar Questions

  1. Match the following lists :

    List – IList – II  
    a. PCMi. Slope overload distortion
    b. DMii. Constant carrier frequency
    c. AMiii. Encoding
    d. TDMiv. Commutator

    The correct match is :

  2. Match the following :

    List – I  List – II
    a. DSB-SC modulationi. envelope detection
    b. SSB-modulationii. Foster Seeley
    c. AM-demodulationiii. Weaver's method
    d. Phase-shift detectioniv. Balanced modulator

    Codes :

  3.   Match the following :

    List – I List – II
    a. Power efficient transmissioni. SSB-SC
    b. Most bandwidth efficient transmission of voice signalii. VSB
    c. Simplest receiveriii. FM
    d. Bandwidth efficient transmission of signals with significant d.c. componentiv. AM

    Codes :

  4. Match List - I with List - II.

    List - IList - II  
    (A) White noise(I) Reduces antenna height
    (B) RMS noise voltage(II) \(P_{C}\left(\dfrac{m^{2}}{2}\right)\)
    (C) Modulation(III) Inversely proportional to \(\sqrt{T}\)
    (D) PDSBSC(IV) Johnson Noise

    Choose the correct answer from the options given below :

  5. Match the following lists :

    List -I List - II
    a. Power efficient transmission of signalsi. AM
    b. Bandwidth efficient transmission of signals with significant dc signalsii. VSB
    c. Most bandwidth efficient transmission of voice signalsiii. SSB-SC
    d. Simplest Receiver Circuitiv. FM

     

    Correct Codes are :

  6. Arrange in order of the increasing Bandwidth value for the below mentioned systems :

    (a) DSB-SC      (b) VSB      (c) FM       (d) SSB

    Codes :


Important Questions from Modulation

  1. Which of the following modulations is used in India for radio transmission?

  2. Which of the following is a result of over-modulation?
  3. Which of the following statements are correct?

    A. DSB‐SC modulation is well suited for point to point communication involving one transmitter and one receiver.

    B. VSB modulation is a linear modulation scheme.

    C. SSB is a non‐linear modulation scheme.

    D. FM is a linear modulation scheme.

    Choose the correct answer from the options given below:

  4. The condition for achieving distortion-less demodulation of an amplitude-modulated signal using an envelope detector is

  5. When a broadcast AM transmitter is 50 % modulated, its antenna current is 12 A. What will be the current when the modulation depth is increased to 90%?

Need Expert Advice?
Upcoming Exams
MH SET
October 25, 2026
CTET
December 12, 2026
Test Series
UGC NET img
Teaching
UGC NET (Paper 1) 2026 Mock Test Series
516 Tests 1 Tests Free
130 Attempts
4.3(131)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App