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Question

Match the following lists :

List – IList – II  
a. PCMi. Slope overload distortion
b. DMii. Constant carrier frequency
c. AMiii. Encoding
d. TDMiv. Commutator

The correct match is :

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

a-iii, b-i, c-ii, d-iv

 Each entry in List II is the defining feature of exactly one system, so the matching is direct: a-iii, b-i, c-ii, d-iv — option 4.

SystemFeatureWhy
a. PCMiii. EncodingSamples are quantised and coded as binary words
b. DMi. Slope overload distortionFixed step size cannot follow a fast input
c. AMii. Constant carrier frequencyAmplitude varies; frequency does not
d. TDMiv. CommutatorRotating switch samples the channels in turn

Slope overload — the characteristic defect of delta modulation. DM transmits one bit per sample, moving its staircase approximation up or down by a fixed step \(\Delta\) at each clock instant. The fastest the staircase can climb is therefore

\(\dfrac{\Delta}{T_{s}}=\Delta f_{s}\)

and if the input rises faster than this the approximation falls behind and cannot catch up until the input slows. The condition for avoiding it is

\(\Delta f_{s}\ge\left|\dfrac{dm(t)}{dt}\right|_{max}=A\omega_{m}\)

The opposite fault, granular noise, appears when the step is too large for a slowly varying input, so the staircase hunts about it. Adaptive delta modulation varies the step size to escape both — which is exactly what the fixed step of plain DM cannot do.

Encoding is what makes PCM digital. Sampling and quantising alone give PAM levels; the encoder turns each level into an n-bit word, and it is that step which buys regeneration and noise immunity.

The commutator is the classic picture of time-division multiplexing: a rotating switch that touches each channel in turn, giving every one its own time slot, with a matching de-commutator at the receiver kept in step by frame synchronisation. Contrast frequency-division multiplexing, where all channels are present at once but in different frequency bands.

Constant carrier frequency distinguishes AM from the angle-modulation family: in AM the envelope carries the message and the frequency stays put; in FM and PM the amplitude stays put and the frequency or phase carries the message.

Hence, the correct match is a-iii, b-i, c-ii, d-iv.

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Similar Questions

  1. Match the following :

    List – I  List – II
    a. DSB-SC modulationi. envelope detection
    b. SSB-modulationii. Foster Seeley
    c. AM-demodulationiii. Weaver's method
    d. Phase-shift detectioniv. Balanced modulator

    Codes :

  2.   Match the following :

    List – I List – II
    a. Power efficient transmissioni. SSB-SC
    b. Most bandwidth efficient transmission of voice signalii. VSB
    c. Simplest receiveriii. FM
    d. Bandwidth efficient transmission of signals with significant d.c. componentiv. AM

    Codes :

  3. Match List - I with List - II.

    List - IList - II  
    (A) White noise(I) Reduces antenna height
    (B) RMS noise voltage(II) \(P_{C}\left(\dfrac{m^{2}}{2}\right)\)
    (C) Modulation(III) Inversely proportional to \(\sqrt{T}\)
    (D) PDSBSC(IV) Johnson Noise

    Choose the correct answer from the options given below :

  4. Match the following lists :

    List - IList - II
    a) i) Frequency modulated detector
    b) ii) Pre-emphasis
    c)  iii)  Amplitude modulator
    d) iv) Amplitude detector

    Choose the correct answer from the codes given below:

  5. Match the following lists :

    List -I List - II
    a. Power efficient transmission of signalsi. AM
    b. Bandwidth efficient transmission of signals with significant dc signalsii. VSB
    c. Most bandwidth efficient transmission of voice signalsiii. SSB-SC
    d. Simplest Receiver Circuitiv. FM

     

    Correct Codes are :

  6. Arrange in order of the increasing Bandwidth value for the below mentioned systems :

    (a) DSB-SC      (b) VSB      (c) FM       (d) SSB

    Codes :


Important Questions from Modulation

  1. Which of the following modulations is used in India for radio transmission?

  2. Which of the following is a result of over-modulation?
  3. Which of the following statements are correct?

    A. DSB‐SC modulation is well suited for point to point communication involving one transmitter and one receiver.

    B. VSB modulation is a linear modulation scheme.

    C. SSB is a non‐linear modulation scheme.

    D. FM is a linear modulation scheme.

    Choose the correct answer from the options given below:

  4. The condition for achieving distortion-less demodulation of an amplitude-modulated signal using an envelope detector is

  5. When a broadcast AM transmitter is 50 % modulated, its antenna current is 12 A. What will be the current when the modulation depth is increased to 90%?

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