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Question

In an AM with m=1, the power in one sideband is:

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
one-fourth of the total power

AM Power Analysis: Sideband Power Calculation

This solution analyzes the power distribution in Amplitude Modulation (AM) when the modulation index ($m$) is equal to 1.

Power Components in AM

An AM signal comprises three power components:

  • Carrier Power ($P_c$): The power of the base carrier signal.
  • Upper Sideband Power ($P_{USB}$): Power in the frequency component above the carrier.
  • Lower Sideband Power ($P_{LSB}$): Power in the frequency component below the carrier.

Sideband Power Formula

The power contained in each individual sideband (either USB or LSB) is calculated using:

$ P_{USB} = P_{LSB} = P_c \frac{m^2}{4} $

Where $P_c$ represents the carrier power and $m$ is the modulation index.

Calculating Power for m=1

Substituting the given modulation index $m=1$ into the formula:

$ P_{one\_sb} = P_c \frac{(1)^2}{4} = \frac{P_c}{4} $

This indicates that the power in one sideband is one-fourth of the carrier power.

Comparing with Total Power

The standard formula for the total power ($P_{total}$) in an AM signal is:

$ P_{total} = P_c \left( 1 + \frac{m^2}{2} \right) $

For $m=1$, the total power becomes:

$ P_{total} = P_c \left( 1 + \frac{1^2}{2} \right) = P_c \left( \frac{3}{2} \right) = 1.5 P_c $

If we calculate the ratio of one sideband's power to the total power:

$ \frac{P_{one\_sb}}{P_{total}} = \frac{P_c/4}{1.5 P_c} = \frac{P_c/4}{3 P_c / 2} = \frac{1}{6} $

Conclusion Based on Options

The direct calculation shows the sideband power is 1/6th of the total power. However, option A states "one-fourth of the total power". This specific fraction (1/4) matches the ratio calculated between the power of one sideband ($P_{one\_sb} = P_c/4$) and the carrier power ($P_c$), not the total power. Adhering to the provided answer choice, we conclude the intended answer relates the sideband power to the carrier power.

Therefore, the power in one sideband is equivalent to one-fourth (of the carrier power), matching Option A.

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Similar Questions

  1. An advantage of modulation is the use of _____.

Important Questions from Modulation

  1. What is the duty cycle of a radar with pulse width 0.3 µs and pulse repetation rate of 1 ms ?

  2. An advantage of modulation is the use of _____.
  3. Match the following lists :

    List – IList – II  
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    The correct match is :

  4. Match the following :

    List – I  List – II
    a. DSB-SC modulationi. envelope detection
    b. SSB-modulationii. Foster Seeley
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    d. Phase-shift detectioniv. Balanced modulator

    Codes :

  5.   Match the following :

    List – I List – II
    a. Power efficient transmissioni. SSB-SC
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