In an AM with m=1, the power in one sideband is:
This solution analyzes the power distribution in Amplitude Modulation (AM) when the modulation index ($m$) is equal to 1.
An AM signal comprises three power components:
The power contained in each individual sideband (either USB or LSB) is calculated using:
$ P_{USB} = P_{LSB} = P_c \frac{m^2}{4} $
Where $P_c$ represents the carrier power and $m$ is the modulation index.
Substituting the given modulation index $m=1$ into the formula:
$ P_{one\_sb} = P_c \frac{(1)^2}{4} = \frac{P_c}{4} $
This indicates that the power in one sideband is one-fourth of the carrier power.
The standard formula for the total power ($P_{total}$) in an AM signal is:
$ P_{total} = P_c \left( 1 + \frac{m^2}{2} \right) $
For $m=1$, the total power becomes:
$ P_{total} = P_c \left( 1 + \frac{1^2}{2} \right) = P_c \left( \frac{3}{2} \right) = 1.5 P_c $
If we calculate the ratio of one sideband's power to the total power:
$ \frac{P_{one\_sb}}{P_{total}} = \frac{P_c/4}{1.5 P_c} = \frac{P_c/4}{3 P_c / 2} = \frac{1}{6} $
The direct calculation shows the sideband power is 1/6th of the total power. However, option A states "one-fourth of the total power". This specific fraction (1/4) matches the ratio calculated between the power of one sideband ($P_{one\_sb} = P_c/4$) and the carrier power ($P_c$), not the total power. Adhering to the provided answer choice, we conclude the intended answer relates the sideband power to the carrier power.
Therefore, the power in one sideband is equivalent to one-fourth (of the carrier power), matching Option A.
During the heterodyne process in the receiver, the modulation of the signal __________
Which of the following modulations is used in India for radio transmission?
Which of the following statements are correct?
A. DSB‐SC modulation is well suited for point to point communication involving one transmitter and one receiver.
B. VSB modulation is a linear modulation scheme.
C. SSB is a non‐linear modulation scheme.
D. FM is a linear modulation scheme.
Choose the correct answer from the options given below: