Indicate the major product of the following reaction:
To determine the major product of the given reaction, we need to analyze the reaction conditions and the substrate provided.
The reaction involves a cyclohexane derivative with a bromine (Br) substituent and is treated with sodium methoxide (\(\text{CH}_3\text{ONa}\)) in methanol (\(\text{CH}_3\text{OH}\)). This is a typical setup for an E2 elimination reaction.
Step-by-step explanation:
- The substrate has a bromine atom which is a good leaving group. The sodium methoxide acts as a strong base.
- In the E2 elimination process, the base abstracts a β-hydrogen (a hydrogen on the carbon adjacent to the carbon with the leaving bromine group) and the leaving group departs simultaneously. This results in the formation of a double bond.
- The most stable alkene (generally the more substituted one due to Saytzeff's rule) will be the major product.
- In our substrate, the bromine is adjacent to a carbon which has deuterium (D) and hydrogen (H). The hydrogen is removed preferentially over deuterium due to kinetic isotopic effect, resulting in the formation of the most stable double bond.
The product with a double bond formed is illustrated below:
Conclusion: The major product is the more stable alkene formed by E2 elimination. This explains why the correct structure matches the provided correct answer image.
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