The products X and Y in the following reaction sequence are
To solve for the products X and Y in the given reaction sequence, let's analyze each step of the reaction:
- Step 1: Reduction with \(Na\) in Liquid Ammonia
- The initial compound is anisole, which undergoes the Birch reduction. In this reduction, sodium (Na) in liquid ammonia is used.
- The electron-rich methoxy group directs the reduction to occur at the para- and ortho- positions relative to itself.
- This typically leads to the formation of a 1,4-cyclohexadiene structure.
- Step 2: Reaction with \(CHBr_3/EtONa\) (Haloform Reaction)
- In the subsequent step, the intermediate compound reacts with bromoform (CHBr3) and sodium ethoxide (EtONa), which serves as a base.
- This combination is known for providing conditions for further transformations, often involving the formation of a carboxylate salt from methyl ketones.
- In our context, this reaction doesn't lead to typical haloform conversion but rather stabilizes intermediate formations.
Hence, the application of these reactions leads to intermediates which further stabilize to form compound Y.
Thus, the products X and Y are as follows:
Explanation: The final product is selected based on possible reductions and derivative stability, in line with known organic reactions, which matches the option provided with this structure.
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The major products U and V in the following reaction are
