The question asks for the original principal sum (sum) based on the interest earned during the second year of compounding and the annual interest rate.
For annual compounding, the interest earned specifically in the nth year is given by:
Interest in nth year = $ P \times \left(1 + \frac{R}{100}\right)^{n-1} \times \frac{R}{100} $
Here, $P$ is the principal, $R$ is the rate, and $n$ is the year.
Substitute the values for the 2nd year ($n=2$):
₹6,258 = $ P \times \left(1 + \frac{20}{100}\right)^{2-1} \times \frac{20}{100} $
Simplify the equation:
₹6,258 = $ P \times \left(1 + 0.20\right)^{1} \times 0.20 $
₹6,258 = $ P \times (1.20) \times 0.20 $
₹6,258 = $ P \times 0.24 $
Solve for the principal sum ($P$):
$ P = \frac{₹6,258}{0.24} $
Perform the division:
$ P = \frac{625800}{24} = ₹26,075 $
Therefore, the principal sum is ₹26,075.
Find the interest (in ₹) on ₹8,000 at 10% per annum compounded half yearly for $1\frac{1}{2}$ years.
The difference between the simple interest and the compound interest, compounded annually, on a certain sum of money for 2 years at 17% per annum is ₹967. Find the sum [rounded off to the nearest integer].