Question
If 8085 microprocessor adds 87H and 79H, then :
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CUET PG 2026 Agri-Business Management Question Paper (25-Mar-2026) (Shift 2)
The correct answer is
Both CARRY and ZERO flags will be set to 1
8085 Microprocessor Addition of 87H and 79H
This solution explains the state of the CARRY and ZERO flags after adding $87H$ and $79H$ in an 8085 microprocessor.
Flag Calculation Steps
First, convert the hexadecimal numbers to binary:
- $87H$ = $1000 0111$2
- $79H$ = $0111 1001$2
Next, perform the binary addition:
| Carry | 1 | 1 | 1 | 1 | 1 | ||||
| 1 | 0 | 0 | 0 | 0 | 1 | 1 | 1 | ||
| + | 0 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | |
| = | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
The sum is $100000000$2.
In 8-bit microprocessor arithmetic, the result is the lower 8 bits, and any bit shifted beyond the 8th position is the carry.
- Result: The lower 8 bits are $00000000$2.
- Carry Out: There is a carry generated from the 8th bit (MSB).
Flag States
Based on the addition result:
- ZERO Flag (Z): The result $00000000$2 is zero. Therefore, the ZERO flag is set to $1$.
- CARRY Flag (CY): A carry was generated out of the most significant bit during the addition. Therefore, the CARRY flag is set to $1$.
Both the CARRY flag and the ZERO flag are set to $1$.
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